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jok3333 [9.3K]
3 years ago
7

PLs help...............

Mathematics
2 answers:
lina2011 [118]3 years ago
7 0

Answer:

your answer is a. x = 11

Step-by-step explanation:

Move all terms that don't contain x to the right side and solve.

Natali5045456 [20]3 years ago
5 0

Answer: The solution is x=11

Step-by-step explanation:

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Solve -6x+19 = x-2. Check for extraneous solutions.
Eddi Din [679]

Answer:

C. x = 3

Step-by-step explanation:

Step 1:

- 6x + 19 = x - 2

Step 2:

- 7x + 19 = - 2

Step 3:

- 7x = - 21

Step 4:

21 = 7x

Answer:

3 = x

Hope This Helps :)

3 0
3 years ago
Read 2 more answers
A student found the product of 6 x 10^5 and 5 x 10^6 to be 3 x 10^11. What is the error? What is the correct product? Complete t
Rainbow [258]
The student is off by a power of 10

The answer is 3 x 10^12
3 0
3 years ago
Find the measurement which is most accurate to 45.76 kg.
svlad2 [7]

Answer:

  A. 45.77 kg

Step-by-step explanation:

The measurement with the smallest difference from 45.76 is 45.77 kg.

4 0
3 years ago
g 1) The rate of growth of a certain type of plant is described by a logistic differential equation. Botanists have estimated th
alexira [117]

Answer:

a) The expression for the height, 'H', of the plant after 't' day is;

H = \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \cdot t}}

b) The height of the plant after 30 days is approximately 19.426 inches

Step-by-step explanation:

The given maximum theoretical height of the plant = 30 in.

The height of the plant at the beginning of the experiment = 5 in.

a) The logistic differential equation can be written as follows;

\dfrac{dH}{dt} = K \cdot H \cdot \left( M - {P} \right)

Using the solution for the logistic differential equation, we get;

H = \dfrac{M}{1 + A\cdot e^{-(M\cdot k) \cdot t}}

Where;

A = The condition of height at the beginning of the experiment

M = The maximum height = 30 in.

Therefore, we get;

5 = \dfrac{30}{1 + A\cdot e^{-(30\cdot k) \cdot 0}}

1 + A = \dfrac{30}{5} = 6

A = 5

When t = 20, H = 12

We get;

12 = \dfrac{30}{1 + 5\cdot e^{-(30\cdot k) \cdot 20}}

1 + 5\cdot e^{-(30\cdot k) \cdot 20} = \dfrac{30}{12} = 2.5

5\cdot e^{-(30\cdot k) \cdot 20} =  2.5 - 1 = 1.5

∴ -(30·k)·20 = ㏑(1.5)

k = ㏑(1.5)/(30 × 20) ≈ 6·7577518 × 10⁻⁴

k ≈ 6·7577518 × 10⁻⁴

Therefore, the expression for the height, 'H', of the plant after 't' day is given as follows

H = \dfrac{30}{1 + 5\cdot e^{-(30\times 6.7577518 \times 10^{-4}) \cdot t}} =  \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \cdot t}}

b) The height of the plant after 30 days is given as follows

H =  \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \cdot t}}

At t = 30, we have;

H =  \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \times 30}} \approx 19.4258866473

The height of the plant after 30 days, H ≈ 19.426 in.

3 0
3 years ago
What is (xy)7 in expanded form
Natali5045456 [20]

Answer:

7xy

Step-by-step explanation:

multiply the outside of the brackets by the inside so it is 7xy

3 0
3 years ago
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