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allochka39001 [22]
3 years ago
8

A race is 10 km long markers will be placed at the beginning and the end of the race course and I each 500 m Mark how many marke

rs are needed to mark the course for the race?
Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
6 0
20 Markers are needed to mark the course for the race
Alinara [238K]3 years ago
3 0
There are 20 marks needed!
You might be interested in
25)
kvasek [131]
C.) 24

The equation must be simplified first
8 0
2 years ago
Find the coordinates of the vertex for the parabola defined by the given quadratic function f(x) = (x + 2)^2 + 2 a) (0,2) b) (2.
Step2247 [10]

Answer:

(-2,2)

Step-by-step explanation:

Let's find the answer.

Because a tangent line for a parabola function is equal to 0 only at its vertex then:

f(x)=(x+2)^{2}+2

f'(x)=2*(x+2)

f'(x)=2x+4 so then:

f'(x)=0 when

0=2x+4

-2=x

For x=-2 f(x) is:

f(x)=(x+2)^{2}+2

f(1)=(-2+2)^{2}+2

f(x)=2

In conclusion, the vertex of the given parabola is (-2,2), so the answer is C. Although in your answer is reported as (-2.2) but I think was a typing mistake.

7 0
2 years ago
A company makes 140 bags.
alexandr402 [8]
38 of the bags have zips but no buttons
3 0
2 years ago
Suppose that z=6^500. Express the following in terms of z.
Studentka2010 [4]

Answer:

1. z^2

2. 14z

Step-by-step explanation:

  • We know that (a^m)^n = a^(mn) = (a^n) ^m

We also know that (a^m)(a^n) = a^(m+n)

  1. 36 can be written as 6^2 and here 36^(500) can be written as (6^2)^500 which also can be written as (6^500)^2 and as already it is mentioned that 6^500 as z we can write the above as <u>z^2</u>

2. 8 x 6^500 = 8z

And we can also write 6^(501) as 6^(500+1) which is equivalent to 6(6^500) which is 6z.

From the above we can make sure that the question is the sum of the above which is 8z + 6z = <u>14z</u><u>.</u>

7 0
2 years ago
How many subsets of five elements each can be made from a set of seven elements?
Alina [70]
<span>When creating a subset of 5 elements from 7 elements, order should not matter. Therefore, we use the combination formula over the permutation formula. The combination formula given n elements total and r elements used is n! / [r!*(n-r)!]. Substituting 7 for n and 5 for r, we get: 7! / (5!*2!) = 7*6 / 2 = 21 21 subsets can be created</span>
8 0
2 years ago
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