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allochka39001 [22]

3 years ago

8

A race is 10 km long markers will be placed at the beginning and the end of the race course and I each 500 m Mark how many marke

rs are needed to mark the course for the race?

2 answers:

sweet-ann [11.9K]3 years ago

6 0

20 Markers are needed to mark the course for the race

Alinara [238K]3 years ago

3 0

There are 20 marks needed!

You might be interested in

What's the next number? 0 , 1/3 , 1/2 , 3/5 , 2/3

madam [21]

Answer:

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 is 5/7

Step-by-step explanation:

The given numbers are;

0, 1/3, 1/2, 3/5, and 2/3

The number sequence is formed adding $\dfrac{1}{\left (\dfrac{n^2 + n}{2} \right ) }$ to each (n - 1)th term to get the nth term number in the sequence, with the first term equal to 0, as follows;

For the 2nd term, the (n - 1)th term is 0, and n = 2, gives;

The

$0 +\dfrac{1}{\left (\dfrac{2^2 + 2}{2} \right ) } = 0 + \dfrac{1}{3} = \dfrac{1}{3}$

For the 3rd term, the (n - 1)th term is 1/3, and n = 3, gives;

$\dfrac{1}{3} +\dfrac{1}{\left (\dfrac{3^2 + 3}{2} \right ) } = \dfrac{1}{3} + \dfrac{1}{6} = \dfrac{1}{2}$

For the 4th term, the (n - 1)th term is 1/2, and n = 4, gives;

$\dfrac{1}{2} +\dfrac{1}{\left (\dfrac{4^2 + 4}{2} \right ) } = \dfrac{1}{2} + \dfrac{1}{10} = \dfrac{3}{5}$

For the 5th term, the (n - 1)th term is 3/5, and n = 5, gives;

$\dfrac{3}{5} +\dfrac{1}{\left (\dfrac{5^2 + 5}{2} \right ) } = \dfrac{3}{5} + \dfrac{1}{15} = \dfrac{2}{3}$

For the next or 6th term, the (n - 1)th term is 2/3, and n = 6, gives;

$\dfrac{2}{3} +\dfrac{1}{\left (\dfrac{6^2 + 6}{2} \right ) } = \dfrac{2}{3} + \dfrac{1}{21} = \dfrac{15}{21} = \dfrac{5}{7}$

The next number of the series 0, 1/3, 1/2, 3/5, and 2/3 = 5/7.

6 0

3 years ago

The rabbit population of Springfield, Ohio was 144,000 in 2016. It is expected to decrease by about 7.2% per year. Write an expo

xeze [42]

<h2>Hello!</h2>

The answer is:

In 2036 there will be a population of 32309 rabbits.

<h2>Why?</h2>

We can calculate the exponential decay using the following function:

$P(t)=StartAmount*(1-\frac{percent}{100})^{t}$

Where,

Start Amount, is the starting value or amount.

Percent, is the decay rate.

t, is the time elapsed.

We are given:

$StartAmount=144,000\\x=7.2(percent)\\t=2036-2016=20years$

Now, substituting it into the equation, we have:

$P(t)=StartAmount(1-\frac{percent}{100})^{t}$

$P(t)=144000*(1-\frac{7.2}{100})^{20}$

$P(t)=144000*(1-0.072)^{20}$

$P(t)=144000*(0.928)^{20}$

$P(t)=144000*(0.928)^{20}$

$P(t)=144000*0.861=32308.888=32309$

Hence, we have that in 2036 the population of rabbis will be 32309 rabbits.

Have a nice day!

5 0

3 years ago

Please help, need answer ASAP!!

salantis [7]

It should be all real numbers

7 0

3 years ago

Elana is programming a video game. She needs to simulate the power up that the player gets when they reach a certain level. The

zvonat [6]

Answer:

You have to define when the power should be pushed up using the 'For' statement and let an impulse be sent to the CPU to increase power by 15%

Step-by-step explanation:

We use certain functions in writing computer programs.

For the 'For' statement ; we can define conditions. First Elana would define at what point does she want the player power to get the best power.

For example if she defines that when the player has played for 2hours return an integer 1 for instance.

This value returned will now send a pulse to the CPU to increase its power to 15%.

If the player plays for further 1hour she can define the count to be 10 and so send another pulse to the CPU to increase the processing power by additional 15%

7 0

3 years ago

Write the next three terms of the sequence.

Arada [10]

Answer:

25, 34, 43

Step-by-step explanation:

-11 + x = -2, -11 + 9 = -2 -2 + x = 7, -2 + 9 = 7, 7 + 9 = 16 -2 - x = -11, -2 - 9 = -11 7 - x = - 2, 2 + x = 11, 11 - 2 = 9, 9 = x 7 - 7 = 0 - 2 = -2, 7 + 2 = 9, 7 - 9 = -2

16 + 9 = 25, 25 + 9 = 34, 34 + 9 = 43

J'espère que cela pourra aider : )

4 0

3 years ago