Answer:
Its A and B i beleive.
Step-by-step explanation:
Answer:
25306
Step-by-step explanation:
a=starting value = 20000
r=\text{rate = }4\% = 0.04
r=rate = 4%=0.04
\text{Exponential Growth:}
Exponential Growth:
b=1+r=1+0.04=1.04
b=1+r=1+0.04=1.04
\text{Write Exponential Function:}
Write Exponential Function:
y=20000(1.04)^x
y=20000(1.04)
x
Put it all together
\text{Plug in time for x:}
Plug in time for x:
y=20000(1.04)^{6}
y=20000(1.04)
6
y= 25306.38037
y=25306.38037
Answer: option D is the correct answer.
Step-by-step explanation:
The given sequence is a geometric sequence because the consecutive terms differ by a common ratio.
The formula for determining the nth term of a geometric progression is expressed as
an = a1r^(n - 1)
Where
a1 represents the first term of the sequence.
r represents the common ratio.
n represents the number of terms.
From the information given,
a1 = 36
r = 12/36 = 4/12 = 1/3
Therefore, the formula for the nth term of the sequence is
an = 36 × 1/3^(n - 1)
an = 36 × 3^-1(n - 1)
an = 36 × 3^(-n + 1)
an = 36 × 3^(1 - n)
Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
