For the first question the answer is D
For the second question the answer is B
Explanation:
The phenotypes and genotypes of the progeny can be determined by a dihybrid cross of the parents.
The heterozygous male will have the genotype 'SSww' and the heterozygous female will have the genotype 'ssWW'.
When crossed, the F1 offsprings will have a hybrid genotype of 'SsWw'. These offsprings are heterozygous with spotted skin and wooly hair.
On self-crossing of the F1 hybrids, we find four different combinations of the alleles- SW, Sw, SW and sw. The probability of getting each of these combinations is 1/4.
Hence, the probability of any dihybrid type is 1 out of the 16 possible genotypes. Using Punnet square, we find
9 SSWW: 3 SSww: 3 ssWW : 1 ssww
This is the phenotypic ratio of the offsprings.
The ratio of the possible genotypes will be 1:2:1:2:4:2:1:2:1.
All blood enter in the right side of the heart through two vein they are called superior vena cava also stand for SVC and the inferior vena cava also stands for SVC
The SVC collects blood from the upper half of the body and the ICC collects blood from the lower half of the body.
And also the blood leaves the SVC and IVC and enters the right atrium
Decomposers are those organisms that recycle matter in the ecosystem.