The correct answer is D) 0,81
When there is Hardy-Weinberg equilibrium like in this case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes. And we have:
p²+2*p*q+q²= 1 <em>p+q= 1 p=1-q</em>
q= 0.1 p= 1-0.1= 0.9
p²=0.9²= 0.81
Answer: .374 and .626
Explanation:
5. total number of alleles = 4712 + 2816 = 7528
frequencey of B allele = B allele / total number of alleles --> 2816/7528 = 0.374
6. total number of alleles = 4712 + 2816 = 7528
freq of b allele = b allele/total number of alleles --> 4712/7528 = 0.626
We can confirm our answer as correct because if we add up the answers to 5 and 6 we should get one:
0.374 + 0.626 = 1
Answer:
They are transformed by the armies of the United States and China wants to defeat them
Answer:
plant propagation
Explanation:
Plant propagation is the process which grows new plants from a variety of sources: seeds, cuttings, and other plant parts. Plant propagation can also refer to the man-made or natural dispersal of seeds.
