2 years ago

A line that passes through [-7,3] and [-6,-1]

Mathematics

1 answer:

juin [17]2 years ago

3 0

Sorry idk, but I’ll try to do it

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Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

$(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0$

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$x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}$

This condition must be observed for the case of a quadratic equation with equal roots:

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3 years ago