Step-by-step explanation:
∫ dt / (cos²(t) ⁹√(1 + tan(t)))
If u = 1 + tan(t), then du = sec²(t) dt.
∫ du / ⁹√u
∫ u^(-1/9) du
9/8 u^(8/9) + C
9/8 (1 + tan(t))^(8/9) + C
Answer:
y = root under 24 (evaluate it if necessary)
or y = 2 root 6
Step-by-step explanation:
Let the reference angle be x
for the triangle in left,
b = 6-4 = 2
Now,
taking x as refrence angle,
cosx = b/h
or, cosx = 2/h
again,
for the bigger triangle,
taking x as reference angle,
cosx = b/h
or, cosx = b/6
As we can see base of bigger triangle is equal to hypotenuse of triangle at the left,
Let's suppose its a
so, cosx = a/6 = 2/a
now,
a/6 = 2/a
or, a² = 12
now,
for bigger triangle, using pythagoras theorem,
h² = p²+b²
or, 6² = y² + a²
or, 36 = y² + 12
or, y² = 24
so, y = root under 24
