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3 years ago

Seee the attachment photo plz

Mathematics

1 answer:

Ray Of Light [21]3 years ago

7 0

Answer:

not sure

Step-by-step explanation:

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The area of a rectangular rug is 25.5 square meters. The width of the rug is 3.75 meters. Found the length of the rug by dividin

Grace [21]

6.8 because 25.5/3.75 = 6.8

8 0

3 years ago

Read 2 more answers

I need help in this section please!!

MrRissso [65]

Answer:

$\frac{1}{25}$

Step-by-step explanation:

Probability of first yellow ball $=\frac{total\ yellow\ ball}{Total\ ball}=\frac{2}{10}=\frac{1}{5}$

Since first ball is again placed in the bag

Probability of second yellow ball $=\frac{total\ yellow\ ball}{Total\ ball}=\frac{2}{10}=\frac{1}{5}$

These two are independent events so the probability of both yellow balls= $=\frac{1}{5} \times \frac{1}{5} =\frac{1}{25}$

7 0

3 years ago

Destiny makes earrings and bracelets to sell. She makes a profit of $15 for

asambeis [7]

Answer:

$135

Step-by-step explanation:

She would make 9 pairs of earrings, they have the least cost and the highest profit. No other combination would yield a higher profit.

5 0

3 years ago

What is the solution to the equation StartFraction y Over y minus 4 EndFraction minus StartFraction 4 Over y + 4 EndFraction = S

Citrus2011 [14]

Answer:

Step-by-step explanation:

Given:

(y/y - 4) - (4/y + 4) = 32/y^2 - 16

Note y^2 - 16 = (y - 4 ) × (y + 4)

Multiplying the equation; both sides by y^2 - 16,

y (y + 4) - (4(y - 4)) = 32

y^2 + 4y - 4y + 16 = 32

y^2 = 32 - 16

Squaring both sides,

y = sqrt(16)

= 4

8 0

3 years ago

Read 2 more answers

A box contains 15 resistors. twelve of them are labelled 50ω and the other three are labeled 100ω. what is the probability that

Igoryamba

Answer : P(second resistor is 100ω , given that the first resistor is 50ω) is given by

$\frac{1}{5}$

Explanation :

Since we have given that

Total number of resistors =15

Number of resistors labelled with 50ω = 12

Number of resistors labelled with 100ω =3

Let A: Event getting resistor with 50ω

B: Event getting resistor with 100ω

Since A and B are independent events .

So,

$P(A\cap B)=P(A).P(B)$

Now, According to question , we can get that

$P(A)= \frac{12}{15}=\frac{4}{5}\\\\P(B)=\frac{3}{15}=\frac{1}{5}$

So,

$P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=\frac{4}{5}\times \frac{1}{5}\\\\P(A\cap B)=\frac{4}{25}$

So, by using the conditional probability , which state that

$P(B\mid A)=\frac{P(A\cap B)}{P(A)}$

$P(B\mid A)=\frac{\frac{4}{25}}{\frac{4}{5}}\\\\P(B\mid A)=\frac{5}{25}\\\\P(B\mid A)=\frac{1}{5}$

So, P(second resistor is 100ω , given that the first resistor is 50ω) is given by

$\frac{1}{5}$

4 0

3 years ago

Seee the attachment photo plz​

Seee the attachment photo plz