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kifflom [539]
3 years ago
6

The meteorologist recorded the amount of rainfall, in centimeters, at 10 different locations during 1 day and then arranged the

amounts from smallest to largest. The amounts were 2, 2, 2, 2, 3, 3, 3, 4, 4, and 5 cm. The mean of these measurements is 3 cm. What is the mean absolute deviation?
0.0 cm
0.8 cm
1.0 cm
2.5 cm
Mathematics
2 answers:
yKpoI14uk [10]3 years ago
8 0

Answer with Step-by-step explanation:

We are given a data :

2, 2, 2, 2, 3, 3, 3, 4, 4, 5  

and its mean is 3

Mean absolute deviation means arithmetic mean of the absolute deviation about mean.

Deviation about mean is:

2-3,2-3,2-3,2-3,3-3,3-3,3-3,4-3,4-3,5-3

-1,-1,-1,-1,0,0,0,1,1,2

absolute deviation about mean is:

1,1,1,1,0,0,0,1,1,2

Arithmetic mean of the absolute deviation is:

1+1+1+1+0+0+0+1+1+2/10

= 8/10

= 0.8 cm

Pepsi [2]3 years ago
7 0
0.8cm 
Just took the test :) 
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s2008m [1.1K]
63 miles in 270 minutes will mean that nolan rides his bike at a distance of 63/270 miles in one minute.
there are 60 minutes in an hour. So to find out the distance he covers in 1 hour, 63/270 × 60 will give you 14 miles.
Since the question is asking for the average speed, nolan rides his bike at 14 miles per hour i think.
4 0
3 years ago
How many numbers greater than zero and less than 50 equal the product of two consecutive positive integers?
spin [16.1K]
Consecutive numbers would be like 2 and 3, or 7 and 8.

All we need to do is keep multiplying pairs of consecutive numbers until we get above 50.

1 × 2 = 2 (that's one.)
2 × 3 = 6 (two)
3 × 4 = 12 (three)
4 × 5 = 20 (four)
5 × 6 = 30 (five)
6 × 7 = 42 (six...)
<em>7 × 8 = 56 > 50</em>
We have a total of 6 numbers that equal the product of 2 consecutive intergers<em>

</em>
7 0
3 years ago
An electric utility company determines the monthly bill for a residential customer by adding an energy charge of 7.32 cents per
Sedaia [141]

Answer:

y(x) = 0.0732x + 17.32

Step-by-step explanation:

The equation for the monthly charge has the following format

y(x) = ax + b

In which y(x) is the cost in function of the number of kilowatt-hours used(x), a is the price of each killowatt hour and b is the fixed(base) charge.

Base charge of $17.32 per month.

This means that b = 17.32

charge of 7.32 cents per kilowatt-hour

Our answer is in dollars. Each dollar is 100 cents. So 7.32 cents is a = 0.0732

Write an equation for the monthly charge y in terms of x, the number of kilowatt-hours used.

y(x) = ax + b

y(x) = 0.0732x + 17.32

6 0
3 years ago
Which statement is true about the extreme value of the given quadratic equation?
ICE Princess25 [194]

Answer:

Option B.  The equation has a maximum value with a y-coordinate of -21.

Step-by-step explanation:

The correct quadratic equation is

y=-3x^{2}+12x-33

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

Convert to vertex form

Factor -3

y=-3(x^{2}-4x)-33

Complete the square

y=-3(x^{2}-4x+2^2)-33+12

y=-3(x^{2}-4x+4)-21

Rewrite as perfect squares

y=-3(x-2)^{2}-21

The vertex is the point (2,-21)

therefore

The equation has a maximum value with a y-coordinate of -21

3 0
3 years ago
A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i
garri49 [273]

Answer:

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :  

Null hypothesis:\mu \leq 5  

Alternative hypothesis:\mu > 5  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

The degrees of freedom first given by:  

df=n-1=12-1=11  

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

6 0
3 years ago
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