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mezya [45]
2 years ago
5

Find the area of a circle with radius, r = 6.82m. Give your answer rounded to 2 DP.

Mathematics
1 answer:
ladessa [460]2 years ago
7 0

Answer:

42.8

Step-by-step explanation:

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Work out the perimeter of this semicircle with radius 3cm. Give your answer in terms of π​
kondaur [170]

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

A semicircle is given with radius of 3cm .

And we need to find the perimeter of the semicircle . We know the perimeter as ,

:\implies Perimeter = πr

:\implies Perimeter = 3cm × π

:\implies Perimeter = 3π cm .

Now there is the diameter of circle is 6cm . Hence totally the perimeter is ,

:\implies Perimeter = 3π + 6 cm

We were supposed to give answers in terms of π .

<h3>Hence the perimeter is ( 3π + 6 ) cm</h3>
5 0
2 years ago
The equation x2 − 6x − 27 = 0 when solved is:
Amiraneli [1.4K]

Answer:

-3 , 9

Step-by-step explanation:

Sum = - 6

Product = -27

Factors = 3, -9

x² - 6x-27 = 0

x² + 3x - 9x - 9*3 = 0

x(x + 3) - 9(x + 3)  = 0

(x + 3) (x - 9) = 0

x +3 = 0   ; x - 9 = 0

x = - 3     ; x = 9

Solution: x = -3 , 9

8 0
3 years ago
5.
Paha777 [63]

Step-by-step explanation:

30 minutes x an hour and half past prolly around 1 hr and 30 sec

5 0
3 years ago
Three listening stations located at (3300, 0), (3300, 1100), and (-3300, 0) monitor an explosion. The last two stations detect t
erastovalidia [21]

Answer:

The coordinates of the explosion is (3300, -2750)

Step-by-step explanation:

I have plot the points and attached to thus answer for easy understanding.

Now, from the question, since station A is the first to hear the explosion, we'll make it the foci of the parabola in the graph I attached and it will be horizontal since the distance between station C and A is much more than that between station B and A. Thus, the reason why station C will have to be the other foci with the hyperbola centred at the origin.

Now, sound travels at a speed of 1100 ft/s and station B is located 1100 ft from station A. Thus, the explosion would likely have occurred at a point on the line x = 3300ft . Since station A is 3300ft from centre C = 3300,hence C² = 3300² = 10,890,000. Since it takes 4 seconds longer for the sound to reach station C than A, the sound has traveled 4(1100)= 4400 ft.

Thus, 4400 = d1 = d2 = 2a

So,2a = 4400 and so, a =2200

a² = 2200² = 4,840,000 where d1 is the distance from station C to the explosion and d2 is the distance from station A to the explosion. To find b², let's use the equation ;

c² = a² + b² and so; b² = c² - a² = 10,890,000 - 4,840,000 = 6,050,000

Equation of hyperbola is given as;

(x²/a²) - (y²/b²) = 1

Plugging in the values of a² and b², we obtain ;

(x²/4,840,000) - (y²/6,050,000) = 1

Since we have deduced that the explosion must occur on the line x= 3300, we'll put in 3300 for x to obtain ;

(3300²/4,840,000) - (y²/6,050,000) = 1

2.25 - 1 = (y²/6,050,000)

y² = (1.25 x 6,050,000)

y² = 7562500

y = √7562500

y = ± 2750

Due to the fact that the explosion will occur at a point further from station B than from station A, the explosion will take place in quadrant 4. Thus, we will take the negative value of y which is - 2750.

So explosion will occur at the coordinate (3300, -2750)

7 0
2 years ago
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