<span>Given, y^2 - 14y = -44
Add 44 to both sides of the equation
</span>y^2 - 14y + 44 = -44 + 44<span>
</span>y^2 - 14y + 44 = 0
Using the quadratic formula x = [-b ± √(b² - 4ac)]/2a
Where,
a = 1
b = -14
c = 44
x = [-b ± √(b² - 4ac)]/2a
x = [-(-14) ± √(-14² - 4(1)(44)]/2(1)
x = [14 ± √(196 - 176)]/2
x = [14 ± √20]/2
x = (14 + √20)/2 OR (14 - √20)/2
x = (14 + 4.472)/2 OR (14 - 4.472)/2
x = 18.472/2 OR 9.528/2
x = 9.236 OR 4.764
The solution set is {9.236, 4.764}
TO EXPRESS THE ANSWER IN RADICALS
x = [14 ± √20]/2
x = (14 + √20)/2 OR (14 - √20)/2
x = (14 + 2√5)/2 OR (14 - 2√5)/2
<span>x = 7+√5 OR 7-√5
</span>
The solution set is {7+√5, 7-√5}
Answer:
54
Step-by-step explanation:
rgefgyhjkdguiofguioWEGRFIUG
Word form: Six hundred thousand plus eighty thousand plus ten
Number form: 600,000+80,000+10
Answer: (2.54,6.86)
Step-by-step explanation:
Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.
We assume the incomes are normally distributed.
Mean income : 
Standard deviation : 
The confidence interval for the population mean (for sample size <30) is given by :-
Given significance level : 
Critical value : 
We assume that the population is normally distributed.
Now, the 95% confidence interval for the true mean will be :-
Hence, 95% confidence interval for the true mean= (2.54,6.86)
Answer:
missing exponent is ^3
Step-by-step explanation:
