F(x)= 0.02x^2 + 0.08x + 30.6
so for f(0) all that means is where you see x plug 0 for x..
f(0)= 0.02(0)^2+ 0.08(0) + 30.6
f(0)= 30.6
f(4)= 0.02(4)^2 + 0.08(4) + 30.6
f(10)= 0.02(10)^2 + 0.08(10) + 30.6
attached are calculated answers
Answer:
The units are 7 away from each other.
Step-by-step explanation:
To find the amount, simply subtract the smaller number from the higher number.
1 - -6 = 7
Answer:
28, 56, 84, 112, etc.
Step-by-step explanation:
Since 28 is the first number they have in common, 28 is the least common multiple of 4 and 7.
Answer:
The correct option is
The origin is included in the shaded region and the shaded area is below the line.
Step-by-step explanation:
Y>3/2x + 2
Put x=0
Y= 2
(0,2)
Put y=0
X= -4/3
(-4/3,0)
See attached picture for the sketch
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
