Expand the following. In other words, remove the parentheses (brackets):

Thirty- five out of sixty students preferred to eat their lunch at school rather going home in lunch break. Express the numbers

IceJOKER [234]

Answer:

0.583

Step-by-step explanation:

Use a caluclator

6 0

2 years ago

Lucy throws a fair six sided dice . so like the letter that matches the probability of the dice landing on a number between 1 an

irakobra [83]

Answer:

Letter B matches the probability.

Step-by-step explanation:

Lucy throws a fair six sided dice.

Probability of the dice landing on a number between 1 and 6 = $\frac{\text{Favorable outcome}}{\text{Number of events}}$

= $\frac{1}{6}$

On a number line fraction $\frac{1}{6}$ can be represented by,

An small section (A to B) will represent the fraction = $\frac{1}{6}$

Therefore, letter B will match the probability of a dice landing on a number between 1 and 6.

4 0

2 years ago

What is the value of 27÷(−34⋅−45)? 4 16/15 28 4/5 45

MakcuM [25]

Answer:

It would not be any of those answers. it would be 106 :) Its negative numbers divided

5 0

2 years ago

Gaetano spent $37.80, including tax, on a pair of jeans. How much did the jeans cost if there was an 8% sales tax? And what is t

Galina-37 [17]

37.8*0.08=3.024
37.8-3.024=34.776
round to the nearest tenths place for currency
and the answer is $34.78

6 0

2 years ago

3. Solve the system using elimination (not substitution or matrices). negative 2 x plus y minus 2 z equals negative 8A N D7 x pl

riadik2000 [5.3K]

Elimination Method

$\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ 5X+2Y-Z=-9 \end{gathered}$

If we multiply the equation 3 by (-1) we obtain this:

$\begin{gathered} -2X+Y-2Z=-8 \\ 7X+Y+Z=-1 \\ -5X-2Y+Z=9 \end{gathered}$

If we add them we obtain 0, therefore there are infinite solutions. So, let's write it in terms of Z

1. Using the 3rd equation we can obtain X(Y,Z)

$\begin{gathered} 5X=-9-2Y+Z \\ X=\frac{-9-2Y+Z}{5} \\ \end{gathered}$

2. We can replace this value of X in the 1st and 2nd equations

$\begin{gathered} -2\cdot(\frac{-9-2Y+Z}{5})+Y-2Z=-8 \\ 7\cdot(\frac{-9-2Y+Z}{5})+Y+Z=-1 \end{gathered}$

3. If we simplify:

$\begin{gathered} \frac{-9Y+12Z-63}{5}=-1 \\ \frac{9Y-12Z+18}{5}=-8 \end{gathered}$

4. We can obtain Y from this two equations:

$\begin{gathered} Y=-\frac{-12Z+58}{9} \\ \end{gathered}$

5. Now, we need to obtain X(Z). We can replace Y in X(Y,Z)

$\begin{gathered} X=\frac{-9-2Y+Z}{5} \\ X=\frac{-9-2(-\frac{-12Z+58}{9})+Z}{5} \end{gathered}$

6. If we simplify, we obtain:

$X=\frac{-3Z+7}{9}$

7. In conclusion, we obtain that

(X,Y,Z) =

$(\frac{-3Z+7}{9},-\frac{-12Z+58}{9},Z)$

8 0

8 months ago