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Twenty-seven is % of 60 help mee asap

jok3333 [9.3K]

Answer: The answer is: " 45 % " .

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→ " Twenty-seven is 45 % of 60. "

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Step-by-step explanation:

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The question asks:

" 27 is what % {percentage] of 60 " ? ;

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So: " 27 = (n/100) * 60 " ; Solve for "n" ;

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Method 1:

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→ (n/100) * 60 = 27 ;

Divide each side by 60 :

→ [ (n/100) * 60 ] / 60 = 27 /60 ;

to get:

→ (n/100) = 27/60 ;

Now: Cross-factor multiply:

→ 60n = (27)*(100) ;

to get:

→ 60n = 2700 ;

Divide each side by "60" ;

→ 60n = 2700/ 60 ;

to get: n = 45 ;

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→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

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Method 2:

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The question asks:

" 27 is what % {percentage] of 60 " ?

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To solve this problem:

Rephrase this question as:

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" 27 is 60% of what number ? "

→ The answer will be the same!

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→ 27 = (60/100)* n ; Solve for "n" ;

Multiply each side of the equation by "100" ; to eliminate the fraction:

→ 100 * 27 = 100 * [ (60/100)* n ] ;

to get:

→ 2700 = 60n ;

↔ 60n = 2700 ;

Divide Each Side of the equation by "60" ;

→ 60n/60 = 2700 / 60 ;

to get: n = 45 ;

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→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

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Method 2: Variant 1 of 2:

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When we have:

→ 27 = (60/100)* n ; Solve for "n" ;

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Note that: "(60/100) = (60÷ 100) = (6 ÷ 10)" ; since: in "(60/100)" ; the "zero" from the "numerator" cancels out; And: the "last zero" in "100" — from the "denominator" cancels out; since we are dividing "each side" of the fraction by "10" ;

→ "(60÷10) / (600÷10)" = " 6/10 " ;

→ " (6/10)" ; that is; "six-tenths"} ;

→ can be represented by: " 0.6 " ;

→ {by convention; but specifically, here is the explanation} — as follows:

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→ "(6/10)" = " (6 ÷ 10) " ;

Note: When dividing a number by "10" ; we take the original number; and move the decimal point to the left; & then we rewrite that number as the "answer".

Note: When multiplying or dividing by a positive, non-zero integer factor of "10" that has at least 1 (one) "zero" after that particular factor of "10". We can get the answer by taking the original number & moving the decimal point the number of spaces as designated by the number of zeros following the particular [aforementioned factor of "10".].

We move the decimal point to the right if we are multiplying; and to the left if we are dividing. In this case, we are dividing "6" by "10 " :

→ " 6 ÷ 10 = ? " ;

→ " 6. ÷ 10 = ? " ;

We take the: " 6. " ; and move the decimal point "one space backward [i.e. "to the left"]; since we are dividing by "10" ;

→ to get: " .6 " ; & we rewrite this value as "0.6" in a rewritten equation:

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So; we take our equation:

→ 27 = (60/100)*n ; And rewrite—substituting "0.6" for

"(60/100)"— as follows:

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→ 27 = (0.6)n ; ↔ (0.6) n = 27 ;

Multiply each side of the equation by "10" ; to eliminate the decimal:

→ 10 * [ (0.6)n ] = 27 * 10 ;

to get:

→ 6n = 270 ;

Divide each side of the equation by "6" ; to isolate "n" on one side of the equation; & to solve for "n" ;

→ 6n / 6 = 270 / 6 ;

to get: n = 45 ;

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→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

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Method 2 (variant 2 of 2):

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We have the equation: 27 = (60/100)* n ; Solve for "n" ;

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Note: From Method 2 (variant) 1 of 2— see above):

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Note: Refer to the point at which we have:

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→ " { (60÷10) / (600÷10)" = " (6/10) " ; that is; "six-tenths"} ;

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Note that the fraction— "(6/10)" ; can be further simplified:

→ "(6/10)" = "(6÷2) / (10÷2)" = "(3/5)" ;

Now, we can rewrite the equation;

→ We replace "(60/100)" ; with: "(3/5)" :

→ 27 = (3/5)* n ; Solve for "n" ;

↔ (3/5)* n = 27 ;

↔ (3n/5) = 27 ;

Multiply Each Side of the equation by "5" ;

→ 5* (3n/5) = 27 * 5 ;

to get:

→ 3n = 135 ;

Divide Each side of the equation by "3" ; to isolate "n" on one side of the equation; & to solve for "n" ;

→ 3n / 3 = 135 / 3 ;

to get: n = 45 ;

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→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

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Hope this answer is helpful!

Wishing you the best in your academic endeavors

— and within the "Brainly" community!

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7 0

3 years ago

Read 2 more answers

Pls help this is major, ill mark u brainliest

Lera25 [3.4K]

Answer:

105

Step-by-step explanation:

$A=lw$ $A=$ (.5)πr²

to get the area of the shaded parts you have to subtract the area of the semicircle from the area of the rectangle

$A=(16)(9)$

$A=144$

$A=\frac{(3.14)(5)^2}{2}$ $A=\frac{(3.14)(25)}{2}$ $A=\frac{78.5}{2}$

$A=39.25$

subtract the areas

$144-39.25=104.75$

$104.75$ ≅ $105$

4 0

3 years ago

Lily goes to gym once every 8 days. Ann goes once every 12 days and Taylor comes once every 16 days. This Wednesday all of them

ahrayia [7]

<h3>Answer:</h3><h3>All of them meet at the gym again after 48 days and it will be tuesday</h3>

Step-by-step explanation:

Lily goes to gym once every 8 days.

Such that she will visit on 8, 16 , 24, 32 , 40, 48th days

Ann goes once every 12 days

Such that she will visit on 12, 24, 36, 48, 60th days ....

Taylor comes once every 16 days

Such that she will visit on 16, 32, 48, 64th days....

Comparing the common days on which they will visit again after wednesday,

it will be after 48 days, (i.e) after 6 weeks and 5 days, it will be tuesday

3 0

3 years ago

Read 2 more answers

LOL ANOTHER MATH QUESTION ASAP!!!

Inessa05 [86]

Your answer is the first one q

6 0

3 years ago

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A $96.00 item is marked down by 25%.

tangare [24]

Answer:

72.00$

Step-by-step explanation:

25% = .25

.25 × 96.00 = 24

96 - 24 = 72

6 0

3 years ago

Read 2 more answers