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bagirrra123 [75]
2 years ago
7

Alice, a vulnerability assessment engineer at a bank, is told to find all the vulnerabilities on an internet-facing web applicat

ion server running on port https. When she finishes the vulnerability scan, she finds several different vulnerabilities at different levels. How should she proceed?.
SAT
1 answer:
Finger [1]2 years ago
3 0

When finding several different vulnerabilities at different levels in a web application server, Alice, the vulnerability assessment engineer must look at vulnerability priority and accuracy.

<h3 /><h3>Web vulnerabilities</h3>

Occurs when there is a weakness or failure of web-based software, which can be derived from misconfiguration, non-validation, and application programming flaws, which can impact information security.

Therefore, it is essential that Alice observes the priority and accuracy of the vulnerabilities found to establish corrections in a faster and more objective way that generate the minimization of security risks for the banking company.

The correct answer is:

  • Note vulnerability priority and accuracy.

Find out more information about web vulnerabilities here:

brainly.com/question/21173478

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Your answer would be D. He is on the honor roll. This explains that he has achieved something some great.
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You stop at a red light
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A sample of a compound that contains only the elements c, h, and n is completely burned in o2 to produce 44. 0 g of co2, 45. 0 g
Elan Coil [88]

Answer:

B. CH₅N

Explanation:

The combustion reaction of a compound CₐHₓNₙ with O₂ is:

CₐHₓNₙ + O₂ → a CO₂ + X/2 H₂O + n NO₂

Where 1 mole of CₐHₓNₙ with an excess of O₂ produce a moles of CO₂, X/2 moles of H₂O and n moles of NO₂

Thus, you need to convert the mass of CO₂ and H₂O to moles to find the C:H ratio and determine a possible empirical formula thus:

Moles CO₂ (Molar mass 44g/mol):

44g ₓ (1mol / 44g) = 1 mole CO₂ = 1 mole C

Mole of H₂O (Molar mass 18g/mol):

45g ₓ (1 mol / 18g) = 2.5 moles H₂O = 5 moles H

Thus, in the compound you have 5 moles of H per mole of C, and a possible empirical formula is:

B. CH₅N

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8 0
2 years ago
A grocery store has two recycling machines
Thepotemich [5.8K]

Answer is 112%

kinda skeptical about my answer but i am going to give it my best shot, sorry if i get it wrong.

In percent-type questions I always go by this formula:

not a %                            %

original number       :     100%

new number            :      new %

original number × new %  =  new number × 100%

here, the original numbers are 240 and 180 and the new % is +30% and -10% now let plastic be P and metal be M and let's elaborate this a bit further

plastic:

the first recycling machine took in 240  plastic bottles while the second took in 30% <u>more</u> plastic bottles, what we have to do here is to find out how much bottles the second machine took in as a form of integer, which is the new number; let that new number be X, let's plug this in the formula

240:100+30\\X:130 \\

notice: 130 is the new %

240*130 = 100X\\31200 = 100X\\312=X

the second machine took in 312 plastic bottles, let's save this answer for later

metal:

the first recycling machine took in 180 metal cans while the second took in 10% <u>less</u> plastic bottles, we do the same thing and find the new number, this time let it be Y:

180:100-10\\Y=90

90 is the new % here; also, notice how sometimes you either add or subtract percents, depending on what the problem demands.

180*90=100Y\\16200=100Y\\162=Y

Now we can conclude that the first recycling machine took in 240  plastic bottles and 180 metal cans and the second took in 312 plastic bottles and 162 metal cans.

here comes the hardest bit to apprehend and the final part of this problem, "the second machine recycled what percent (%) more items than the first?"

in other words, how much percent did the second machine recycle more.

to find that percent, first we need to add the plastic and metal "items" of both machines individually and turn them into percents: let the first machine be A and second machine be B:

A: 240+180=420

B: 312+162=474

again, using the same formula to find the new percent, let that percent be Z; plugging both A and B respectively:

420:100\\474:Z

420Z=474*100\\420Z=47400\\Z= 112.857≈ 112% more items than the first

now if you check the rounded up 112 and plug it back in to make sure of your answer: 420Z=47400 you end up getting 47040, since it's rounded up, but when you plug the full 112.857 you get 47399.94, closest to 47400. Tip: when you plug in any value for check up, don't use the rounded up one.

At last, those steps are actually fast, especially with that formula it's so important. the explanation seems intimidating so read it slowly and take your time. if you have any other questions, feel free to ask. also, let me know if you know a faster method to solve this question. <3

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