You can try to show this by induction:
• According to the given closed form, we have
, which agrees with the initial value <em>S</em>₁ = 1.
• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

and

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

From the given recurrence, we know

so that






which is what we needed. QED
Answer:
h = 9 cm.
Step-by-step explanation:
V = kBh where k is the constant of variation.
From the given info:
32 = k*16*6 = 96k
So k = 32/96 = 1/3.
So we have the equation of variation:
V = 1/3Bh
When V = 60 B = 20, so:
60 = 1/3 20h
20h = 60 * 3 = 180
h = 180 /20 = 9.
How to solve your problem
Answer:
AB=29; BC=27
Step-by-step explanation:
So they told us AB=4x+9 and that BC=5x+2, and AC=56 , now to help with the question you can draw this information on a number line. Now on a number you can see that basically AC=AB+BC.
So you would write it as such,,
4x+9+5x+2=56
Combine like terms
9x+11=56
Now you have to isolate the x by itself but first get rid of the 11.
9x+11-11=56-11
You would get
9x=45
Here you can divide 9 by both sides to isolate x.
9x/9=45/9
{x=5}
Now to find the value for both substitue x in the equations for both
1. AB=4x+9 where x is 5
4(5)+9 =AB
20+9 =AB
29=AB
You would do the same with BC
2. BC= 5x+2 where x is 5
5(5)+2= BC
25+2= BC
27=BC
If you want to check your answers you can just substitute x for 5 in the first equation we did where AC=AB+BC
Answer:
A 270° rotation about point B'
Step-by-step explanation:
Rotation is clockwise so you can see that the final transformation is a rotation 270° clockwise