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UkoKoshka [18]
3 years ago
11

TJ is think of a number which he calls n he finds 1/3 of the number

Mathematics
2 answers:
Andrew [12]3 years ago
8 0

Answer:

Step-by-step explanation:

Let the number TJ thinks of be n.

If he finds 1/3 of the number, the expression that models this situation is expressed as:

1/3 of n

= 1/3 * n

= n/3

hence the expression that models the scenario is n/3

rosijanka [135]3 years ago
7 0

Answer:

1/3n-5

Step-by-step explanation:

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Yo If anyones awake i really need help
kirill [66]

Answer:

57

Step-by-step explanation:

Straight line value=180

Given Value=123

Value of ∆TKL

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=57(Ans)

3 0
3 years ago
In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en
jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

n(E∩S) = 95

The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

           = 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

any opposite of a natural number is created with a "minus"

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(x2 - 4x + 3) + (3x2 – 3x - 5)
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Answer:

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Step-by-step explanation:

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