Answer:
a. v(t)= -6.78
+ 16.33 b. 16.33 m/s
Step-by-step explanation:
The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=
=
. We now multiply both sides of the equation by the integrating factor.
μv' + μkv = μg ⇒
v' + k
v = g
⇒ [v
]' = g
. Integrating, we have
∫ [v
]' = ∫g
v
= 
+ c
v(t)=
+ c
.
From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have
9.55 = 9.8 × 15/9 + c
= 16.33 + c
c = 9.55 -16.33 = -6.78.
So, v(t)= 16.33 - 6.78
. m/s = - 6.78
+ 16.33 m/s
b. Velocity of object at time t = 0.5
At t = 0.5, v = - 6.78
+ 16.33 m/s = 16.328 m/s ≅ 16.33 m/s
You can divide the total number of outcomes.
Answer:
what are you asking
Step-by-step explanation:
cool?
Answer:
B. 
Step-by-step explanation:
GIven that
and
, and that point M is the midpoint of AB, the midpoint can be determined as a vectorial sum of A and B. That is:

The location of B is now determined after algebraic handling:


Then:




Which corresponds to option B.
Answer:
304m^2
Step-by-step explanation:
First find the surface area of the base by multiplying the length by the width.
(12m) (8m)= 96m^2
Second, find the surface area of the front and back triangles using the formula <em>1/2 (base) (height)</em>. Use the length for the base.
1/2 (12m) (10m)= 60m^2
Next, find the surface area of the side triangles using the formula <em>1/2 (base) (height). </em>Use the width as the base.
1/2 (8m) (11m)= 44m^2
Last, add the surface area of each section. Make sure you add the area of each face.(we only solved for 1 of the front/ back triangles and 1 of the side triangles) To make it easier to understand I wrote out an equation to show how I added the surface areas.
base=a, front/ back triangles= b, side triangles=c
SA= a + 2b +2c or SA= a +b +b +c +c
Using one of the equations above solve for the total surface area.
SA= (96m^2) + (60m^2) +(60m^2) +(44m^2) +(44m^2)
or
SA= (96m^2) + 2(60m^2) +2(44m^2)
SA= (96m^2) +(120m^2) +(88m^2)
SA= 304m^2