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marishachu [46]
3 years ago
8

The function

Mathematics
1 answer:
Ghella [55]3 years ago
8 0

Functions can be represented by equations and graphs

  • There are 2 million users online at 9 am
  • The domain is [0,23], while the range is [2,\infty)

<h3>The number of users at 9am</h3>

The function is given as:

g(x) = \frac 14\sqrt[3]{x - 3} + 2

At 9am, x = 9.

So, we have:

g(x) = \frac 14\sqrt[3]{9 - 3} + 2

Evaluate the difference

g(x) = \frac 14\sqrt[3]{6} + 2

Evaluate the exponent

g(x) = \frac 14 * 1.8 + 2

g(x) = 0.45 + 2

Evaluate the sum

g(x) = 2.45

Approximate

g(x) = 2

Hence, there are 2 million users online at 9 am

<h3>The function transformation</h3>

We have:

g(x) = \frac 14\sqrt[3]{x - 3} + 2

The parent function is:

f(x) = \sqrt[3]{x}

So, the transformations applied to the parent function are:

  • Vertical compression by a scale factor of 4
  • Horizontal shift to the right by 3 units
  • Vertical shift up by 2 units

<h3>The domain and the range</h3>

The domain is the possible input values, and the range are the possible output values.

There are 24 hours in a day.

So, the domain is:

Domain = [0,23]

While the range is [2,\infty)

Read more about function transformation at:

brainly.com/question/1548871

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"Suppose an object falling in the atmosphere has mass m=15kg and the drag coefficient is γ=9kg/s. Recall that the differential e
Art [367]

Answer:

a. v(t)= -6.78e^{-16.33t} + 16.33 b. 16.33 m/s

Step-by-step explanation:

The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=e^{\int\limits^  {}k \, dt } =e^{kt}. We now multiply both sides of the equation by the integrating factor.

μv' + μkv = μg ⇒ e^{kt}v' + ke^{kt}v = ge^{kt} ⇒ [ve^{kt}]' = ge^{kt}. Integrating, we have

∫ [ve^{kt}]' = ∫ge^{kt}

    ve^{kt} = \frac{g}{k}e^{kt} + c

    v(t)=   \frac{g}{k} + ce^{-kt}.

From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have

9.55 = 9.8 × 15/9 + ce^{-16.33 * 0} = 16.33 + c

       c = 9.55 -16.33 = -6.78.

So, v(t)=   16.33 - 6.78e^{-16.33t}. m/s = - 6.78e^{-16.33t} + 16.33 m/s

b. Velocity of object at time t = 0.5

At t = 0.5, v = - 6.78e^{-16.33 x 0.5} + 16.33 m/s = 16.328 m/s ≅ 16.33 m/s

6 0
3 years ago
How can you find the probability of a simple event if the total number of equally likely outcomes is 20?
dimaraw [331]
You can divide the total number of outcomes.
5 0
3 years ago
The pool has a diameter of 5 feet and a height of 3 feet
BigorU [14]

Answer:

what are you asking

Step-by-step explanation:

cool?

6 0
3 years ago
Read 2 more answers
Point A is located at (-2, 2), and point M is located at (1,0). If point M is the midpoint of AB, find the location of point B.
bezimeni [28]

Answer:

B. B = (4,-2)

Step-by-step explanation:

GIven that A = (-2, 2) and M = (1, 0), and that point M is the midpoint of AB, the midpoint can be determined as a vectorial sum of A and B. That is:

M = \frac{1}{2}\cdot A + \frac{1}{2}\cdot B

The location of B is now determined after algebraic handling:

\frac{1}{2}\cdot B = M - \frac{1}{2}\cdot A

B = 2\cdot M -A

Then:

B = 2\cdot (1,0)-(-2,2)

B = (2\cdot 1, 2\cdot 0)-(-2,2)

B = (2,0) -(-2,2)

B = (4,-2)

Which corresponds to option B.

5 0
3 years ago
What is the surface area of this rectangular pyramid?
Alexxx [7]

Answer:

304m^2

Step-by-step explanation:

First find the surface area of the base by multiplying the length by the width.

(12m) (8m)= 96m^2

Second, find the surface area of the front and back triangles using the formula <em>1/2 (base) (height)</em>. Use the length for the base.

1/2 (12m) (10m)= 60m^2

Next, find the surface area of the side triangles using the formula <em>1/2 (base) (height). </em>Use the width as the base.

1/2 (8m) (11m)= 44m^2

Last, add the surface area of each section. Make sure you add the area of each face.(we only solved for 1 of the front/ back triangles and 1 of the side triangles) To make it easier to understand I wrote out an equation to show how I added the surface areas.

base=a, front/ back triangles= b, side triangles=c

SA= a + 2b +2c  or SA= a +b +b +c +c

Using one of the equations above solve for the total surface area.

SA= (96m^2) + (60m^2) +(60m^2) +(44m^2) +(44m^2)

or

SA= (96m^2) + 2(60m^2) +2(44m^2)

SA=  (96m^2) +(120m^2) +(88m^2)

SA= 304m^2

7 0
3 years ago
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