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ziro4ka [17]
3 years ago
6

What is the product of (3y^-4)(2y^-4)?

Mathematics
2 answers:
borishaifa [10]3 years ago
4 0
(x^a)(x^b)=x^(a+b)

(ab)(cd)=(a)(b)(c)(d)

x^-m=1/(x^m)


(3y^-4)(2y^-4)=
(3)(y^-4)(2)(y^-4)=
(6)(y^-8)=
6/(y^8)
lubasha [3.4K]3 years ago
4 0

Answer:

Product of (3y^{-4})(2y^{-4})=6y^{-8}

Step-by-step explanation:

Given : Expression (3y^{-4})(2y^{-4})

To find : The product of the given expression?

Solution :

(3y^{-4})(2y^{-4})

Applying property of exponent, x^a\times x^b=x^{a+b}

Comparing with given expression x=y , a=-4 and b=-4

=(3)\times(2)\times(y^{-4+(-4)})

Multiply 3 and 2,

=6\times(y^{-8})

=6y^{-8}

Therefore, Product of (3y^{-4})(2y^{-4})=6y^{-8}

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Answer: \log\dfrac{x^2z^2}{y}

Step-by-step explanation:

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Step-by-step explanation:

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