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3 years ago

What is the product of (3y^-4)(2y^-4)?

Mathematics

2 answers:

borishaifa [10]3 years ago

4 0

(x^a)(x^b)=x^(a+b)

(ab)(cd)=(a)(b)(c)(d)

x^-m=1/(x^m)

(3y^-4)(2y^-4)=
(3)(y^-4)(2)(y^-4)=
(6)(y^-8)=
6/(y^8)

lubasha [3.4K]3 years ago

4 0

Answer:

Product of $(3y^{-4})(2y^{-4})=6y^{-8}$

Step-by-step explanation:

Given : Expression $(3y^{-4})(2y^{-4})$

To find : The product of the given expression?

Solution :

$(3y^{-4})(2y^{-4})$

Applying property of exponent, $x^a\times x^b=x^{a+b}$

Comparing with given expression x=y , a=-4 and b=-4

$=(3)\times(2)\times(y^{-4+(-4)})$

Multiply 3 and 2,

$=6\times(y^{-8})$

$=6y^{-8}$

Therefore, Product of $(3y^{-4})(2y^{-4})=6y^{-8}$

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