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ziro4ka [17]
3 years ago
6

What is the product of (3y^-4)(2y^-4)?

Mathematics
2 answers:
borishaifa [10]3 years ago
4 0
(x^a)(x^b)=x^(a+b)

(ab)(cd)=(a)(b)(c)(d)

x^-m=1/(x^m)


(3y^-4)(2y^-4)=
(3)(y^-4)(2)(y^-4)=
(6)(y^-8)=
6/(y^8)
lubasha [3.4K]3 years ago
4 0

Answer:

Product of (3y^{-4})(2y^{-4})=6y^{-8}

Step-by-step explanation:

Given : Expression (3y^{-4})(2y^{-4})

To find : The product of the given expression?

Solution :

(3y^{-4})(2y^{-4})

Applying property of exponent, x^a\times x^b=x^{a+b}

Comparing with given expression x=y , a=-4 and b=-4

=(3)\times(2)\times(y^{-4+(-4)})

Multiply 3 and 2,

=6\times(y^{-8})

=6y^{-8}

Therefore, Product of (3y^{-4})(2y^{-4})=6y^{-8}

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225,000 X 2: 450,000

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Anastaziya [24]
That'd be true only if the value of "s" is the exact same one for both
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5 0
3 years ago
In a cave, a stalactite gets 44 millimeters longer each year. this year it is 72 centimeters long. how many years until it is 1
iragen [17]

Answer:

6.36 years (the .36 repeats), so rounded is 6.4.

Step-by-step explanation:

First, I'm going to convert all measurements to meters.

Since 1000 mm = 1 m, divide 44 by 1000.

44/1000 = 0.044 m

Since 100 cm = 1 m, divide 72 by 100.

72/100 = 0.72 m

Next, I'm going to setup an equation using y = mx + b.

b is the beginning amount which is 0.72.

m in the equation represents the rate which is 0.044.

y represents the total which is 1.

Plugin the numbers and solve for x.

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