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Ira Lisetskai [31]
2 years ago
11

50 points!!! Picture below please help

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
6 0

Answer:

24/25

20/29

Step-by-step explanation:

Trigonometry ratios:

sin(\theta)=\frac{O}{H} \\\\cos(\theta)=\frac{A}{H} \\\\tan(\theta)=\frac{O}{A}

where O is the side opposite to the angle, A is the side adjacent to the angle and H is the hypotenuse (longest side)

As angles A and C are complementary, this implies that side b is the hypotenuse and sides a and c are the legs of a right triangle.

Referring to the attached diagram:

sin(A) = O/H = a/b

cos(C) = A/H = a/b

Therefore, sin(A) ≡ cos(C)

If sin(A) = 24/25 , the value of cos(C) = 24/25

If cos(A) = 20/29, the value of sin(C) = 20/29

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~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 3 -5}{2}~~~ ,~~~ \cfrac{ 5 + 9}{2} \right)\implies \left( \cfrac{-2}{2}~~,~~\cfrac{14}{2} \right)\implies \stackrel{center}{(-1~~,~~7)} \\\\[-0.35em] ~\dotfill

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[3 - (-5)]^2 + [5 - 9]^2}\implies d=\sqrt{(3+5)^2+(-4)^2} \\\\\\ d=\sqrt{8^2+16}\implies d=\sqrt{80}\implies d=4\sqrt{5}~\hfill \stackrel{\textit{half the diameter}}{\cfrac{4\sqrt{5}}{2}\implies \underset{radius}{2\sqrt{5}}}

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