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natita [175]
3 years ago
11

It took Ruby 23 minutes to make meatballs and 29 minutes to make tomato sauce. How much time did it take Ruby to make meatballs

and tomato sauce combined?
Mathematics
2 answers:
____ [38]3 years ago
6 0

Answer:

52 minutes unless she was multi-tasking then it took her 29 mins to do all

Step-by-step explanation:

52 minutes

Dahasolnce [82]3 years ago
5 0

It took Ruby 23 minutes to make meatballs and 29 minutes to make tomato sauce. How much time did it take Ruby to make meatballs and tomato sauce combined?

<u>52 minutes! :)</u>

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What is the area of this circle?
Juli2301 [7.4K]

Answer:

The area will be<u> </u><u>113.1</u>

Step-by-step explanation:

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5 0
3 years ago
This expression is factored what is it's trinomal form?<br> (5x+2)(x-3)
Mkey [24]

Answer:

5x² - 13x - 6

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, that is

5x(x - 3) + 2(x - 3) ← distribute both parenthesis

= 5x² - 15x + 2x - 6 ← collect like terms

= 5x² - 13x - 6

8 0
3 years ago
Find the mean and mode for this set of data.<br>5, 6, 8, 3, 5, 7, 4, 11, 5, 7​
dangina [55]

Answer:the mean is 6.1 the mode is 5 and 7.

Step-by-step explanation: the mean is 6.1 because the number add up to 61 and there are 10 numbers 61/10=6.1

The mode is 5 and 7 because they occur most frequently

3 0
3 years ago
2y^4 x 5y^3 please can you help me
Morgarella [4.7K]

Answer:

20y^7. this is because the exponents are added together because the variable attached to the coefficient are the same therefor the coefficients are multiplied, and the exponents are added together.

8 0
2 years ago
Read 2 more answers
Given the following right triangle, find cose, sine, tane sececsce, and cote. Do not
IgorLugansk [536]

Step-by-step explanation:

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have

leg=4,\ hypotenuse=10

Substitute:

4^2+leg^2=10^2

16+leg^2=100             <em>subtract 16 from both sides</em>

leg^2=84\to leg=\sqrt{84}\\\\leg=\sqrt{(4)(21)}\\\\leg=\sqrt4\cdot\sqrt{21}\\\\leg=2\sqrt{21}

sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\cotangent=\dfrac{adjacent}{opposite}\\\\secant=\dfrac{hypotenuse}{adjacent}\\\\cosecant=\dfrac{hypotenuse}{opposite}

Substitute:

hypotenuse=10,\ opposite=4,\ adjacent=2\sqrt{21}

\sin\theta=\dfrac{4}{10}=\dfrac{2}{5}\\\\\cos\theta=\dfrac{2\sqrt{21}}{10}=\dfrac{\sqrt{21}}{5}\\\\\tan\theta=\dfrac{4}{2\sqrt{21}}=\dfrac{2}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{2\sqrt{21}}{21}\\\\\cot\theta=\dfrac{2\sqrt{21}}{4}=\dfrac{\sqrt{21}}{2}\\\\\sec\theta=\dfrac{10}{2\sqrt{21}}=\dfrac{5}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{5\sqrt{21}}{21}\\\\\csc\theta=\dfrac{10}{4}=\dfrac{5}{2}

5 0
3 years ago
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