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2 years ago

Write the equation of the line given two points on the line: (-3,-3) (-5,-3)

Mathematics

1 answer:

Arada [10]2 years ago

8 0

Answer:

y= -3

Step-by-step explanation:

I'll assume it is a linear line (straight line).

Sense the y-value doesn't change and stays -3, the equation for the line would be y= -3

And just so you know, the slope of the line would be 0.

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PLZ HELP!!!!!! (WILL GIVE BRAINLIEST!!!!) Number 4 only

Elan Coil [88]

Figure B, it's volume is 48 while figure A is 36

4 0

3 years ago

The temperature at a point (x, y) is T(x, y), measured in degrees Celsius. A bug crawls so that its position after t seconds is

aniked [119]

Answer:

10.50°C

Step-by-step explanation:

Given x = 2 + t , y = 1 + 1/2t where x and y are measured in centimeters. Also, the temperature function satisfies Tx(2, 2) = 9 and Ty(2, 2) = 3

The rate of change in temperature of the bug path can be expressed using the composite formula:

dT/dt = Tx(dx/dt) + Ty(dy/dt)

If x = 2+t; dx/dt = 1

If y = 1+12t; dy/dt = 1/2

Substituting the parameters gotten into dT/dt we will have;

dT/dt = 9(1)+3(1/2)

dT/dt = 9+1.5

dT/dt = 10.50°C/s

Hence the rate at which the temperature is rising along the bug's path is 10.50°C/s

7 0

3 years ago

A survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10. (a)

skad [1K]

Answer:

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

b) The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

Step-by-step explanation:

Step:-(i)

Given data a survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10

The sample size 'n' = 25

The mean of the sample x⁻ = $28

The standard deviation of the sample (S) = $10.

Level of significance ∝=0.05

The degrees of freedom γ =n-1 =25-1=24

tabulated value t₀.₀₅ = 2.064

Step 2:-

The 95% of confidence intervals for the average spending

( $(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )$

$(28 - 2.064 \frac{10}{\sqrt{25} } ,28 + 2.064\frac{10}{\sqrt{25} } )$

( 28 - 4.128 , 28 + 4.128)

(23.872 , 32.128)

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

Null hypothesis: H₀:μ<30

Alternative Hypothesis: H₁: μ>30

level of significance ∝ = 0.05

The test statistic

$t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }$

$t = \frac{28-30 }{\frac{10}{\sqrt{25} } }$

t = |-1|

The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

Conclusion:-

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

8 0

3 years ago

Please answer! These are due tmr and it's 12:53 rn!

SashulF [63]

1.D
2.D
3.C
4.C
5.D
6.2160
7.288

You really shouldn't be waiting untill 1 AM to do your homework!

5 0

3 years ago

Find the quotient of 436.48and 35.2

denpristay [2]

436.48(35.2)= 15,364.1 :)

8 0

3 years ago