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AnnZ [28]
3 years ago
13

Help plsss it’s 11:08 and due at 11:59

Mathematics
2 answers:
Rashid [163]3 years ago
3 0
There you go! Hopefully this helps.

AlexFokin [52]3 years ago
3 0

Answer:

andre did short division and jada did long division

Step-by-step explanation:

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Use the distributive property to remove the parenthesis<br><br> 2=(v-8)
Tpy6a [65]

Answer:

v = 10

Step-by-step explanation:

2 = v - 8

add 8 to both sides

10 = v

8 0
3 years ago
What is 3 examples of a rate?
atroni [7]

Answer:

Step-by-step explanation: For example, if a 12 ounce can of corn costs 55 cents the rate is 55 cents for 12 ounces. The first term in ratio is measured in cents the second term in ounces

5 0
3 years ago
3/1/2+1/5/6÷1/3/5 <br>hello good afternoon can u please solve this question​
Likurg_2 [28]

Answer:

1/2

Step-by-step explanation:

See the steps below:)

7 0
3 years ago
The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given
slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

\tau = 2438.155\,yr

The particular solution of the differential equation is:

m(t) = 10\cdot e^{-\frac{t}{2438.155} }

d) The amount of radium after 300 years is:

m(300) \approx 8.842\,g

4 0
3 years ago
Read 2 more answers
Clint and Max worked out at the gym together today. Clint works out at the gym every 4 days. Max works out at the gym every 6 da
VikaD [51]

Answer:

24 days

Step-by-step explanation:

To determine the number of days until they both work out at the gym on the same day again,

Find the lowest common multiples of 4 days and 6 days

Clint (4 days) = 8, 12, 16, 20, 24, 28, 32

Max (6 days) = 12, 18, 24, 30, 36, 42

The lowest common multiple of ,4 days and 6 days is 24 days

Therefore, the number of days until they both work out at the gym on the same day again is 24 days

7 0
3 years ago
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