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djverab [1.8K]
2 years ago
5

In what quadrant is the point (-7, -16)? Help!!!!!

Mathematics
2 answers:
svp [43]2 years ago
6 0

Answer:

quadrant 3

Step-by-step explanation:

Andrej [43]2 years ago
6 0

Answer:

Those points are in Quadrant 3

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81(p+q)^2-9p-9q <br> Factor this
polet [3.4K]

Answer:

9(p + q)(9p + 9q - 1)

Step-by-step explanation:

Given

81(p + q)² - 9p - 9q ← factor out - 9 from these 2 terms

= 81(p + q)² - 9(p + q) ← factor out 9(p + q) from each term

= 9(p + q)(9(p + q) - 1)

= 9(p + q)(9p + 9q - 1)

8 0
3 years ago
Read 2 more answers
21. Jesse saved his allowance all summer to by a wake board. He put $36.50 in his piggy bank every two weeks for 3 months. He sp
ddd [48]

So lets start out this problem with the initial amount of money jesse has:

$36.50 x (2 (times a month)) x (3 months) = $219

Then, you take 1/4 of his money (which can be converted to the decimal 0.25) and you subtract it from $219

$219 - ($219 x 0.25)

$219 - $54.75 = $164.25

Next, you have to subtract Jesse's lunch ($14.25) from the money he has left after purchasing his tow rope and bathing suit.

$164.25 - $14.25 = $150

Jesse's wake board cost him $150.

7 0
3 years ago
According to the American Lung Association, 7% of the population has lung disease. Of those having lung disease, 90% are smokers
postnew [5]

Answer:

Probability that a smoker has lung disease = 0.2132

Step-by-step explanation:

Let L = event that % of population having lung disease, P(L) = 0.07

So,% of population not having lung disease, P(L') = 1 - P(L) = 1 - 0.07 = 0.93

S = event that person is smoker

% of population that are smokers given they are having lung disease, P(S/L) = 0.90

% of population that are smokers given they are not having lung disease, P(S/L') = 0.25

We know that, conditional probability formula is given by;

                        P(S/L) = \frac{P(S\bigcap L)}{P(L)}  

                        P(S\bigcap L) = P(S/L) * P(L)

                                      = 0.90 * 0.07 = 0.063

So,  P(S\bigcap L) = 0.063 .

Now, probability that a smoker has lung disease is given by = P(L/S)

      P(L/S) = \frac{P(S\bigcap L)}{P(S)}

P(S) = P(S/L) * P(L) + P(S/L') * P(L')

       = 0.90 * 0.07 + 0.25 * 0.93 = 0.2955

Therefore, P(L/S) = \frac{0.063}{0.2955} = 0.2132

Hence, probability that a smoker has lung disease is 0.2132 .

7 0
3 years ago
You bought two tickets to the movies at a price of $7 and six tickets at a price of $5
Stels [109]

Hello! They answer to your question would be that you spent $44. This was because 7*2=14 and 6*5-30. Therefore, 14+30=44.

4 0
3 years ago
A car travels 2.83 km in the x-direction, then turns left 65.3 ◦ to the original direction and travels an additional distance of
umka21 [38]

Answer:

  4.24 km

Step-by-step explanation:

The x-component of the displacement after the turn is ...

  d2·cos(θ) = (3.38 km)cos(65.3°) ≈ 1.41239 km

Adding this to the displacement before the turn, we have ...

  x-component of displacement = 2.83 km + 1.41 km = 4.24 km

4 0
3 years ago
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