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Sunny_sXe [5.5K]
2 years ago
11

Which relationship has a zero slope? A two column table with five rows. The first column, x, has the entries, negative 3, negati

ve 1, 1, 3. The second column, y, has the entries, 2, 2, 2, 2. A two column table with five rows. The first column, x, has the entries, negative 3, negative 1, 1, 3. The second column, y, has the entries, 3, 1, negative 1, negative 3. A coordinate plane with a straight line starting at (negative 5, negative 5) and passing through the origin, and ending at (5, 5) A coordinate plane with a straight line starting iat (negative 2, 5) and passing the x-axis at (negative 2, 0), and ending at (negative 2, 5). Mark this and return Save and Exit Next Submit
Mathematics
1 answer:
katovenus [111]2 years ago
5 0

Answer:

..........................................................................

Step-by-step explanation:

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(4x+___)+(2x+3)=6x+5<br> Find the missing term.
SOVA2 [1]

Answer:

(4x+2)+(2x+3)=6x+5

Step-by-step explanation:

(4x+___)+(2x+3)=6x+5

4x+2x=6x

5-3=?

5-3=2

2

7 0
2 years ago
Solve xy-6=k for x <br><br><br> Please help me out
dedylja [7]

Answer:

\times  =  \frac{k + 6}{y}

Step-by-step explanation:

xy - 6 = k \\ xy = k + 6 \\ x =  \frac{k + 6}{y}

4 0
2 years ago
What value of b will cause the system to have an infinite number of solutions?
irga5000 [103]

b must be equal to -6  for infinitely many solutions for system of equations y = 6x + b and -3 x+\frac{1}{2} y=-3

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}

Let us bring the equations in same form for sake of simplicity in comparison

\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}

Now we have two equations  

\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}

Let us first see what is requirement for system of equations have an infinite number of solutions

If  a_{1} x+b_{1} y+c_{1}=0 and a_{2} x+b_{2} y+c_{2}=0 are two equation  

\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}} then the given system of equation has no infinitely many solutions.

In our case,

\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}

 As for infinitely many solutions \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}

Hence b must be equal to -6 for infinitely many solutions for system of equations y = 6x + b and  -3 x+\frac{1}{2} y=-3

8 0
3 years ago
jasmine had 11 friends over at her house. everytime the doorbell rang 2 more friends arrived. the doorbell rand 3 times. how man
Lelechka [254]
I'm pretty sure the answer is 17
3 0
3 years ago
How does the figure help verify the triangle inequality theorem?
adelina 88 [10]

The figure description helps; Choice A; by showing that a triangle cannot be formed when the sum of the lengths of two sides is less than the length of the third side.

<h3>What is the triangle inequality theorem?</h3>

The triangle inequalities theorem postulates that the sum of lengths of two sides of a triangle must be greater than the length of the third side.

On this note, it follows that the since the sum of sides given in the description 7 and 4 is less than 15, the segments cannot be used to form a triangle.

Read more on triangle inequalities;

brainly.com/question/22559323

#SPJ1

6 0
1 year ago
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