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Ber [7]
2 years ago
9

Answer I'll give brainliest to first one10 points​

Mathematics
2 answers:
defon2 years ago
7 0

Answer:

Have a splendiferous day...

Step-by-step explanation:

3÷12=¼

6÷10=⅗

7÷14=½

10÷11=⅚

2÷4=½

4÷16=¼

3÷24=⅛

18÷54=⅓

olasank [31]2 years ago
4 0

Answer:

1) 3÷12=\frac{1}{4}

2) 6÷10=\frac{3}{5}

3) 7÷14=\frac{1}{2}

4) 10÷12=\frac{5}{6}

5) 2÷4=\frac{1}{2}

6) 4÷16=\frac{1}4

7) 3÷24=\frac{1}{8}

8) 18÷54=\frac{1}{3}

Step-by-step explanation:

Hope this helps have a great day ahead! Have a great Halloween :) Tell me if im wrong please <3

You might be interested in
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28-81%29x%5E%7B2%7D%20%7D" id="TexFormula1" title="\sqrt{(-81)x^{2} }" alt="\sqrt{(
SSSSS [86.1K]

Answer:

We conclude that:

\sqrt{\left(-81\right)x^2}=9ix

Step-by-step explanation:

Given the radical expression

\sqrt{\left(-81\right)x^2}

simplifying the expression

\sqrt{\left(-81\right)x^2}

Remove parentheses:  (-a) = -a

\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}

Apply radical rule:   \sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0

                 =\sqrt{-1}\sqrt{81x^2}

Apply imaginary number rule:  \sqrt{-1}=i

                 =i\sqrt{81x^2}

Apply radical rule:   \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0

                  =\sqrt{81}i\sqrt{x^2}

                  =9i\sqrt{x^2}

Apply radical rule:  \sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

                  =9ix

Therefore, we conclude that:

\sqrt{\left(-81\right)x^2}=9ix

7 0
2 years ago
Help 20 ptssss asap !
ELEN [110]

Answer:

Assuming you want an equation, y = -4/3x - 1

Step-by-step explanation:

Formula is y = mx + b

m = slope= -4/3

b = y-intercept = -1

4 0
3 years ago
How many 10-digit ternary strings are there that contain exactly two 0s, three 1s, and five 2s?
Svet_ta [14]

There are \dbinom{10}2 ways of picking 2 of the 10 available positions for a 0. 8 positions remain.

There are \dbinom83 ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's \dbinom55=1 way of doing that.

So we have

\dbinom{10}2\dbinom83\dbinom55=\dfrac{10!}{2!(10-2)!}\dfrac{8!}{3!(8-3)!}\dfrac{5!}{5!(5-5)!}=2520

The last expression has a more compact form in terms of the so-called multinomial coefficient,

\dbinom{10}{2,3,5}=\dfrac{10!}{2!3!5!}=2520

5 0
2 years ago
Please do both please answer properly and show how u got ur answer
Sphinxa [80]

Answer:

a) No.

b) Yes.

Step-by-step explanation:

a) It's not proportional. Although the graph represents a straight line, it does not pass through the origin (0,0).

b) It is proportional. It is a straight line that passes through the origin.

6 0
2 years ago
Factorize the following algebraic expression:
Hoochie [10]
X^2+16-38=0
find what 2 numbers multiply to get -38 and add to get 16
find factors of 38
2 times 19
there is no way to use common factor so use quadratic formula which is
x=\frac{ -b+\sqrt{b^2-4ac} }{2a} or x=\frac{ -b-\sqrt{b^2-4ac} }{2a}

ax^2+bx+c=0 subsitte
a=1
b=16
c=-38
subsitute
\frac{ -16+\sqrt{16^2-4(1)(-38)} }{2(1)}=\frac{ -16+\sqrt{256+152} }{2}= \frac{ -16+\sqrt{408} }{2}= \frac{ -16+2\sqrt{102} }{2}=-8+\sqrt{102}
so the answers for x are -8+\sqrt{102} and -8-\sqrt{102}  which are aprox -2.099504938362 and +18.099504938362
so it would be
(x-[-8+√102])(x+[8+√102])=0


6 0
2 years ago
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