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sammy [17]
3 years ago
10

The difference between the most hours of sleep and the least of these students was 2.5 hours. True or false?​

Mathematics
1 answer:
SashulF [63]3 years ago
8 0

The correct anwer is False

Explanation

According to the graph, it can be seen that a student has four hours of sleep as the minimum number of hours of sleep; two students have six hours of sleep, four students have six and a half hours of sleep, four have seven hours of sleep, three have seven and a half hours of sleep, five have eight hours of sleep, and one has eight and a half hours of sleep as maximum hours of sleep. Therefore, it can be affirmed that the statement that the difference between the maximum amount and the minimum number of hours is two and a half hours is false because between four hours and eight and a half hours there are four and a half hours of difference. So, the correct answer is False.

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Find the exact value of sin ( 7 π 4 ) using reference angles
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Answer:

-1/root2

Step-by-step explanation:

7pi/4 radians is the same as -pi/4 radians

sin(-pi/4) is -sin(pi/4) = -1/root2

3 0
4 years ago
Find x, round your answer to the nearest integer.
Makovka662 [10]

Answer:

B. 8

Step-by-step explanation:

cos37° = 4/5 = x/10

=> 4(10) = 5x

=> x = 40/5

=> x = 8

The correct option is B.

8 0
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HELP ASAP!!! WILL GIVE BRAINLIEST! Given that RS=20 and QR=5, identify the length of PS¯¯¯¯¯.
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Step-by-step explanation:

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3 years ago
An older TV screen was 11 centimeters wide. The
Montano1993 [528]

Answer:

The new TV screen is 12.1 centimeters wide.

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4 0
3 years ago
Read 2 more answers
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
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