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xxTIMURxx [149]

2 years ago

5

1.11t can be written as (1.111/12)12t to give the monthly interest rate based on an annual rate of 11%. Transform the expression

into a single exponent expression that gives the approximate equivalent monthly interest rate based on an annual rate of 11%.

1 answer:

Nataly_w [17]2 years ago

5 0

Answer:

yup this explanation is correct you will get good grade

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A coffee shop uses two different-sized bins to store coffee beans. The volume of the smaller bin is r cubic inches and the volum

DaniilM [7]

Answer:

r+y×(S×L)

Step-by-step explanation:

4 0

3 years ago

The profile of the cables on a suspension bridge may be modeled by a parabola. The central span of the bridge is 1210 m long and

brilliants [131]

Answer:

The approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

Step-by-step explanation:

The equation of the parabola is:

$y=0.00035x^{2}$

Compute the first order derivative of <em>y</em> as follows:

$y=0.00035x^{2}$

$\frac{\text{d}y}{\text{dx}}=\frac{\text{d}}{\text{dx}}[0.00035x^{2}]$

$=2\cdot 0.00035x\\\\=0.0007x$

Now, it is provided that |<em>x </em>| ≤ 605.

⇒ -605 ≤ <em>x</em> ≤ 605

Compute the arc length as follows:

$\text{Arc Length}=\int\limits^{x}_{-x} {1+(\frac{\text{dy}}{\text{dx}})^{2}} \, dx$

$=\int\limits^{605}_{-605} {\sqrt{1+(0.0007x)^{2}}} \, dx \\\\={\displaystyle\int\limits^{605}_{-605}}\sqrt{\dfrac{49x^2}{100000000}+1}\,\mathrm{d}x\\\\={\dfrac{1}{10000}}}{\displaystyle\int\limits^{605}_{-605}}\sqrt{49x^2+100000000}\,\mathrm{d}x\\\\$

Now, let

$x=\dfrac{10000\tan\left(u\right)}{7}\\\\\Rightarrow u=\arctan\left(\dfrac{7x}{10000}\right)\\\\\Rightarrow \mathrm{d}x=\dfrac{10000\sec^2\left(u\right)}{7}\,\mathrm{d}u$

$\int dx={\displaystyle\int\limits}\dfrac{10000\sec^2\left(u\right)\sqrt{100000000\tan^2\left(u\right)+100000000}}{7}\,\mathrm{d}u$

$={\dfrac{100000000}{7}}}{\displaystyle\int}\sec^3\left(u\right)\,\mathrm{d}u\\\\=\dfrac{50000000\ln\left(\tan\left(u\right)+\sec\left(u\right)\right)}{7}+\dfrac{50000000\sec\left(u\right)\tan\left(u\right)}{7}\\\\=\dfrac{50000000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+5000x\sqrt{\dfrac{49x^2}{100000000}+1}$

Plug in the solved integrals in Arc Length and solve as follows:

$\text{Arc Length}=\dfrac{5000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+\dfrac{x\sqrt{\frac{49x^2}{100000000}+1}}{2}|_{limits^{605}_{-605}}\\\\$

$=1245.253707795227\\\\\approx 1245.25$

Thus, the approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

7 0

3 years ago

A snow plough has a 3.2m blade set at an angle of 30 degrees How wide a path will the snow plough clear

snow_tiger [21]

Answer:

1.6m

Step-by-step explanation:

The length of the blade is 3.2m

The angle which the blade makes is 30°

Assuming the path of the blade and the length it covers is a right-angled triangle,

The length of the blade is the hypothenus while the path at which it clears is the opposite of the triangle.

See attached document for better illustration.

Using SOHCAHTOA,

Sinθ = opposite / hypothenus

opposite = x

hypothenus = 3.2

θ = 30°

Sin30 = x / 3.2

X = 3.2sin30

X = 3.2 × 0.5

X = 1.6m

The path which the snow plough clears is 1.6m

6 0

3 years ago

What's the simplest from for 15/72

pychu [463]

Divide them both by three and you will get your answer, which is 5/24

4 0

3 years ago

Find the domain of y equals the square root of the quantity 3 multiplied by x plus 3 end of quantity.

juin [17]

Answer:

The answer is D

Step-by-step explanation:

4 0

3 years ago