Answer:
C. Cardinality of set E is equal to that of O
Step-by-step explanation:
We are given that two sets
a set E of non negative even numbers
E={0,2,4,....}
A set O of non negative odd numbers
O={1,3,5,.....}
We have to choose correct option in given options
We know that
Set of non negative even numbers is countably infinite and set of non negative odd numbers is also countably infinite.
Cardinality of countably infinite set=Aleph naught=
Therefore, cardinality of E=
Cardinality of O=
Therefore, the cardinality of set E is equal to cardinality of set O.
Hence, option C is true.
Answer:
B. survey a random sample of 7th-grade students
Step-by-step explanation:
this answer would make the most sense because it is a example of a random statistical question.
Answer:
The answer is option (C)=an-1+7
Step-by-step explanation:
A recursive rule is a formula that in which each term is expressed as a function of its preceding term(s), meaning in order to get to the nth term you have to express it in a form of the term that comes before it. In our case the a(n-1) term
So for the sequence -9, -2, 5, 12
The nth term is any number on the sequence and
- -2 is the a(n-1) term for -9
- 5 is the a(n-1) term for -2
- 12 is the a(n-1) term for 5
So we need to find out what we have to do to the preceding term to get the next.
To get -2 from -9 we have to add 7 to -9; -9+7=-2
To get 5 from -2 we have to add 7 to -2; -2+7=5
To get 12 from 5 we add 7 to 5; 7+5=12
So the recursive rule would be= a n-1+7
