The given values are:
p = 22% = 0.22
Zc = 1.645 at 90% confidence level.
margin of error, E = 0.04
The formula we can use here is:
E = sqrt(pq/n) * Zc
0.04 = sqrt(0.22*(1-0.22)/n)*1.645
n = (0.22*(1-0.22))*(1.645/0.04)^2
n = 290.22
hence minimum sample size = 290
Answer:
Q6: B Q7: D Q8: C Q9: D Q10: A
Is there any answer choices or a picture??
Answer:
D
Step-by-step explanation:
A no = 1/5
B no = 4
C no = 1/3
D yes
E no = 17/50
