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3 years ago

Brainliest if correct

Mathematics

2 answers:

dexar [7]3 years ago

5 0

Answer:

w = 9

Step-by-step explanation:

18 + 4w = 6w

6w - 4w = 2w

2w = 18

18/2 = 9

2w/2 = w

w = 9

Andrew [12]3 years ago

3 0

$\large\textbf{Hey there!}$

$\large\textbf{18 + 4w = 6w}\\\large\textbf{4w + 18 = 6w}\\\large\text{SUBTRACT 62to BOTH SIDES}\\\large\textbf{4w + 18 - 6w = 6w - 6w}\\\large\text{SIMPLIFY IT!}\\\large\textbf{-2w + 18 = 0}\\\large\text{SUBTRACT 18 to BOTH SIDES}\\\large\textbf{-2w + 18 - 18 = 0 - 18}\\\large\text{CANCEL out: 18 - 18 because it give you 0}\\\large\text{KEEP: 0 - 18 because it help solve for the w-value}\\\large\text{NEW EQUATION: \bf -2w = 0 - 18}\\\large\text{SIMPLIFY IT!}\\\large\textbf{-2w = -18}$

$\large\text{DIVIDE -2 to BOTH SIDES}\\\mathbf{\dfrac{2w}{-2}= \dfrac{-18}{-2}}\\\large\text{CANCEL out:} \rm\dfrac{-2}{-2}}\large\text{ because it give you 1}\\\large\text{KEEP: }\rm{\dfrac{-18}{-2}}\large\text{ because it gives you the w-value}\\\large\text{NEW EQUATION: \bf w = }\rm{\bf \dfrac{-18}{-2}}\\\large\text{SIMPLIFY IT!}\\\large\textbf{w = 9}\\\\\huge\textbf{Therefore, your answer is: \boxed{\mathsf{w = 9}}}\huge\checkmark$

$\large\textbf{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

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Step-by-step explanation:

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3 years ago

Sally painted a picture that has an area of 480 square inches. The length of the painting is 1 1/5 its width. Which of the follo

SVETLANKA909090 [29]

L = (1⅕)W= (6/5)W
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8 0

3 years ago

2x+5= -25 and -3m-6= 40 What is the product of x and m?

ivanzaharov [21]

Answer:

Step-by-step explanation:

2x+5= -25 .........(1)

and -3m-6= 40........(2)

Considering (1): 2x+5= -25

2x = -25 - 5

2x = -30

x = -30/2

x = -15

Considering (2): -3m-6= 40

-3m = 40 + 6

-3m = 46

m = -46/3

Product of x and m = (-15) × (-46/3)

= -5 × -46

= 230

4 0

3 years ago

Any 10th grader solve it for 50 points

kkurt [141]

Answer:

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0$ is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.

Step-by-step explanation:

Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.

First term of given arithmetic progression is A

and common difference is D

ie., $a_{1}=A$ and common difference=D

The nth term can be written as

$a_{n}=A+(n-1)D$

pth term of given arithmetic progression is a

$a_{p}=A+(p-1)D=a$

qth term of given arithmetic progression is b

$a_{q}=A+(q-1)D=b$ and

rth term of given arithmetic progression is c

$a_{r}=A+(r-1)D=c$

We have to prove that

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)=0$

Now to prove LHS=RHS

Now take LHS

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)$

$=\frac{A+(p-1)D}{p}\times (q-r)+\frac{A+(q-1)D}{q}\times (r-p)+\frac{A+(r-1)D}{r}\times (p-q)$

$=\frac{A+pD-D}{p}\times (q-r)+\frac{A+qD-D}{q}\times (r-p)+\frac{A+rD-D}{r}\times (p-q)$

$=\frac{Aq+pqD-Dq-Ar-prD+rD}{p}+\frac{Ar+rqD-Dr-Ap-pqD+pD}{q}+\frac{Ap+prD-Dp-Aq-qrD+qD}{r}$

$=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}$

$=\frac{Arq^{2}+pq^{2} rD-Dq^{2} r-Aqr^{2}-pqr^{2} D+qr^{2} D+Apr^{2}+pr^{2} qD-pDr^{2} -Ap^{2}r-p^{2} rqD+p^{2} rD+Ap^{2} q+p^{2} qrD-Dp^{2} q-Aq^{2} p-q^{2} prD+q^{2}pD}{pqr}$

$=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2}-pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}$

$=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2} -pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}$

$\neq 0$

ie., $RHS\neq 0$

Therefore $LHS\neq RHS$

ie., $\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0$

Hence proved

5 0

3 years ago

Find the least common multiple for each list of numbers 5, 7

ddd [48]

Multiples of 5 are: 5,10,15,20,25,30,35,40,45,.......

Multiples of 7 are: 7,14,21,28,35,42,49,63,......

So the least common number is these two sets is 35, which is the least common multiple of 5 and 7

Hope you got it

8 0

3 years ago