1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
netineya [11]
3 years ago
12

Find the radius of a sphere whose surface area is 154cm².​with stepss

Mathematics
2 answers:
worty [1.4K]3 years ago
7 0

Answer:

THIS IS YOUR ANSWER:

area \: of \: spere \:  = 4\pi \: r {}^{2}  \\ 154cm {}^{2} = 4 \times  \frac{22}{7}  \times r {}^{2}

\frac{154 \times 7}{4 \times 22} = r {}^{2} \\ r {}^{2} = 12.25 \\

r =  \sqrt{12.25} \\ r = 3.5cm

<em>✍️</em><em>HOPE</em><em> </em><em>IT HELPS</em><em> </em><em>YOU</em><em> </em><em>✍️</em>

AURORKA [14]3 years ago
7 0

Answer:

The radius of sphere is 3.5 cm.

Step-by-step explanation:

<u>SOLUTION</u> :

Here's the required formula to find the radius of sphere :

\longrightarrow{\pmb{\sf{SA_{(Sphere)}  = 4 \pi{r}^{2}}}}

  • → SA = surface area
  • → π = 22/7
  • → r = radius

Substituting all the given values in the formula to find the radius of sphere :

\longrightarrow{\sf{SA_{(Sphere)}  = 4 \pi{r}^{2}}}

\longrightarrow{\sf{154 = 4 \times  \dfrac{22}{7} \times {r}^{2}}}

\longrightarrow{\sf{154 = \dfrac{88}{7} \times {r}^{2}}}

\longrightarrow{\sf{{r}^{2} = 154 \times  \dfrac{7}{88} }}

\longrightarrow{\sf{{r}^{2} = \dfrac{1078}{88} }}

\longrightarrow{\sf{{r}^{2} = 12.25}}

\longrightarrow{\sf{r = \sqrt{12.25}}}

\longrightarrow{\sf{r = 3.5}}

\star{\boxed{\sf{\pmb{r = 3.5 \: cm}}}}

Hence, the radius of sphere is 3.5 cm.

\rule{200}2

<u>DIAGRAM</u> :

Here's the diagram of sphere with radius 3.5 cm.

\setlength{\unitlength}{1.2cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\qbezier(-2.3,0)(0,-1)(2.3,0)\qbezier(-2.3,0)(0,1)(2.3,0)\thinlines\qbezier (0,0)(0,0)(0.2,0.3)\qbezier (0.3,0.4)(0.3,0.4)(0.5,0.7)\qbezier (0.6,0.8)(0.6,0.8)(0.8,1.1)\qbezier (0.9,1.2)(0.9,1.2)(1.1,1.5)\qbezier (1.2,1.6)(1.2,1.6)(1.38,1.9)\put(0.2,1){\bf{3.5\ cm}}\end{picture}

\rule{300}{2.5}

You might be interested in
A ball is dropped from the top of a building that is 250 feet tall. The
Virty [35]

hi

-16t²+250 = 75

-16t² = 75 -250

-16t² = -175

  t² = -175 /-16

 t² = 175/16

Here there si two solutions :  t = \sqrt{175/16}   and  t =  - \sqrt{175/16}

However, as time cannot rewind,  we will  keep only positive solution

So t = \sqrt{175/16}

   

in seconds  it will be  :  3.3 seconds

3 0
3 years ago
I will give brainiest to whoever answers correctly !!
Salsk061 [2.6K]

Answer:

The interest charged is $7.49.

After 29 days, Travis paid a total of $607.49

Step-by-step explanation:

Travis obtained a cash advance for $600.

The interest rate is 0.04305% per day.

The simple interest rate formula is given by:

I=Prt

Where <em>I</em> is the interest, <em>P</em> is the initial amount, <em>r</em> is the rate, and <em>t</em> is the time (in this case in days).

Our initial amount <em>P</em> is $600.

Our interest rate <em>r</em> is 0.04305% or (moving the decimal two places to the left) 0.0004305.

Since Travis repaid the loan after 29 days, our <em>t</em> is 29.

Hence, our interest is:

I=600(0.0004305)(29)=7.4907

So, the interest charged is about $7.49.

So, after 29 days, Travis paid a total of the original $600 plus an interest of $7.49 for a total of $607.49

6 0
3 years ago
Read 2 more answers
A) Find a recurrence relation for the number of bit strings of length n that contain a pair of consecutive 0s.
Fed [463]

Answer:

A) a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

B) a_{0} = a_{1} = 0

C)   for n = 2

  a_{2} = 1

for n = 3

 a_{3} = 3

for n = 4

a_{4} = 8

for n = 5

a_{5} = 19

Step-by-step explanation:

A) A recurrence relation for the number of bit strings of length n that contain a  pair of consecutive Os can be represented below

if a string (n ) ends with 00 for n-2 positions there are a pair of  consecutive Os therefore there will be : 2^{n-2} strings

therefore for n ≥ 2

The recurrence relation for the number of bit strings of length 'n' that contains consecutive Os

a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

b ) The initial conditions

The initial conditions are : a_{0} = a_{1} = 0

C) The number of bit strings of length seven containing two consecutive 0s

here we apply the re occurrence relation and the initial conditions

a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

for n = 2

  a_{2} = 1

for n = 3

 a_{3} = 3

for n = 4

a_{4} = 8

for n = 5

a_{5} = 19

7 0
3 years ago
What angle relationship describes ∠UQR and ∠WRT?
sashaice [31]

Answer:

corresponding angles because it is in a F pattern shape

always corresponding angle is denoted from F pattern and its sum is always equal

5 0
3 years ago
Read 2 more answers
5. Emmanuel makes 82,000 as a software designer. Use the follow tax chart to find what he will pay in taxes this year.
Mekhanik [1.2K]
I think the answer is d
5 0
3 years ago
Other questions:
  • In the equation x = 24/6, what is the next step in the equation solving sequence
    13·2 answers
  • I will be giving brainliest
    6·2 answers
  • Choose the graph of y = -4 cot x.
    15·1 answer
  • what is the answer to the multiplication problem. Jhon has 20 fish if he lets 6 fish go how many fish dose Jhon have?
    9·1 answer
  • Hey:) can you please help me posted picture of question
    7·2 answers
  • What is the square root if 55
    8·2 answers
  • Lana is using a can opener to open a can of soup. Every time she twists the knob of can opener the can opens 36 degrees. How man
    13·1 answer
  • Least to greatest in order 1/2 , -1/2 , -1/3 , 1/3​
    13·2 answers
  • Find the slope of a line parallel to each given line<br> Y=-3x-1
    15·1 answer
  • In a garden club, 90% i ladie. The number of ladie i 12 more than 3 time the number of gentlemen. How many ladie and how many ge
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!