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3 years ago

PLEASE HELP ASAP!! (NO LINKS)

Mathematics

1 answer:

Keith_Richards [23]3 years ago

7 0

No it isn’t. it works for the first equation but not the second

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Suppose Cotangent (theta) = StartFraction 5 Over 12 EndFraction, where Pi less-than theta less-than StartFraction 3 pi Over 2 En

Agata [3.3K]

Answer:

Sin theta = 12/13

Step-by-step explanation:

From the question;

Cot theta = 5/12

Kindly recall;

Cot theta = 1/ tan theta

Hence, tan theta = 12/5

Mathematically

tan theta= opposite/adjacent

to get hypotenuse, we will use Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides

let hypotenuse be h

h^2 = 12^2 + 5^2

h^2 = 144 + 25

h^2 = 169

h = √169

h = 13

But sine theta = opposite/ hypotenuse = 12/13

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3 years ago

a spherical balloon is deflated at a rate of 256pi/3 cm^3/sec. at what rate is the radius of the balloon changing when the radiu

Hunter-Best [27]

What you need to look for is $\frac { dr }{ dt }$ when r=8.

Now:

$Volume\quad of\quad a\quad sphere:\\ \\ V=\frac { 4 }{ 3 } \pi { r }^{ 3 }$

$\therefore \quad \frac { dV }{ dr } =\frac { 4 }{ 3 } \pi \cdot 3{ r }^{ 2 }=4\pi { r }^{ 2 }\\ \\ \therefore \quad \frac { dr }{ dV } =\frac { 1 }{ \frac { dV }{ dr } } =\frac { 1 }{ 4\pi { r }^{ 2 } }$

$And:\\ \\ \frac { dV }{ dt } =-\frac { 256\pi }{ 3 } \\ \\ Therefore:\\ \\ \frac { dr }{ dt } =\frac { dr }{ dV } \cdot \frac { dV }{ dt }$

$\\ \\ =\frac { 1 }{ 4\pi { r }^{ 2 } } \cdot -\frac { 256\pi }{ 3 } \\ \\ =-\frac { 256 }{ 12 } \cdot \frac { \pi }{ \pi } \cdot \frac { 1 }{ { r }^{ 2 } }$

$\\ \\ =-\frac { 64 }{ 3{ r }^{ 2 } } \\ \\ When\quad r=8,\\ \\ \frac { dr }{ dt } =-\frac { 64 }{ 3\cdot { 8 }^{ 2 } } =-\frac { 1 }{ 3 } \\ \\ Answer:\quad -\frac { 1 }{ 3 } \quad cm/sec$

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3 years ago

Dean is building a tower with blocks as shown in the diagram. The tower shown has three stories

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Answer:

Step-by-step explanation:

divide 80 by 3 and then multiply answer by 15

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3 years ago

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The answer is y=-2x+6

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3 years ago

determine the common difference, the fifth term, the nth term, and the 100th term of the arithmetic sequence.17, 14, 11, 8,

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The common difference of the sequence is -3 and the fifth term is 5

<h3>How to determine the common difference?</h3>

The sequence is given as:

17, 14, 11, 8....

The common difference is

d = T2 - T1

So, we have

d = 14 - 17

Evaluate

d = -3

Hence, the common difference of the sequence is -3

<h3>How to determine the fifth term?</h3>

The fifth term is calculated as:

T5 = a + 4d

Where

a = T1 = 17

d = -3

So, we have:

T5 = 17 - 4 * 3

Evaluate

T5 = 5

Hence, the fifth term is 5

<h3>How to determine the nth term?</h3>

The nth term is calculated as:

Tn = a + (n - 1)d

Hence, the nth term is Tn = a + (n - 1)d

Read more about arithmetic sequence at:

brainly.com/question/6561461

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2 years ago