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3 years ago

| NEED HELP I PLS NEED HELP THIS IS 6TH GRADE

Mathematics

1 answer:

maks197457 [2]3 years ago

3 0

Answer:

480

Step-by-step explanation:

if you add 1/4 4 times for each foot you can multiply them then and get your answer

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A student wants to check six websites. Four of the websites are social and two are school-related. After checking just two sites

mash [69]

The approximate probability that she checked a social website first, then a school-related website is 0.267.

First step is to calculate the Total number of websites

Total number of websites=Number of school websites+Number of social websites

Total number of websites=2+4

Total number of websites=6

Second step

Probability of checking the social website first

Probability of checking social website=Number of social websites/Total number of websites

Probability of checking social website= 4/6

Third step

Since one social website is checked which means that she is left with 3 social website and 2 school websites

Total number websites=2+3

Total number websites=5

Forth step

Probability of checking social website=Number of school websites/Total number websites

Probability of checking social website=2/5

Fifth step

Probability= 4/6 x 2/5 = 0.2666

Probability=0.267(Approximately)

Inconclusion the approximate probability that she checked a social website first, then a school-related website is 0.267.

Learn more about probability here:brainly.com/question/25688842

6 0

3 years ago

In January of 2011, the U.S. saw an increase in gas prices. Imagine the average price per gallon was $3.12 with a standard devia

Arada [10]

Answer:

31.92%

Step-by-step explanation:

We are given;

Population mean; μ = $3.12

Sample mean; x¯ = $3.16

Sample size; n = 10

Standard deviation; σ = $0.27

Z-score formula is; z = (x¯ - μ)/(σ/√n)

z = (3.16 - 3.12)/(0.27/√10)

z = 0.04/(0.08538)

z ≈ 0.47

Now, the percent of other sample means, based on 10 gas stations, that would be greater than the one observed is;

P(x¯ > 3.12) = 1 - P(z < 0.47)

From z-table attached P(z < 0.47) = 0.68082

Thus;

P(z > 0.47) = 1 - 0.68082

P(z > 0.47) ≈ 0.3192

This expressed in percentage is 31.92%

4 0

2 years ago

Misha deposited $3,725 into a savings account 22 years ago. The account has an interest rate of 2.2% and the balance is currentl

Annette [7]

The compounding equation is $A=P(1+ \frac{r}{n}) ^{nt}$ . So

$6012.37 = 3725(1+ \frac{0.022}{n}) ^{22n}$     Divide by 3725

$1.6141= (1+ \frac{0.022}{n}) ^{22n}$

Daily    = $(1+ \frac{0.022}{365}) ^{22*365}$
              = $(1.000060274) ^{8030}$
              = 1.6225
Monthly = $(1+ \frac{0.022}{12}) ^{22*12}$
              = $(1.0018333) ^{264}$
              = 1.6218
Quarter = $(1+ \frac{0.022}{4}) ^{22*4}$
              = $(1.0055) ^{88}$
              = 1.6204
Yearly = $(1+ \frac{0.022}{1}) ^{22*1}$
              = $(1.022) ^{22}$
              = 1.6141

The answer is yearly.

5 0

3 years ago

Can someone please help me with this

Artist 52 [7]

9514 1404 393

Answer:

21. D

22. C

Step-by-step explanation:

21. The expansion of the given expression is ...

$\displaystyle -\frac{1}{2}\left(-\frac{3}{2}x+6x+1\right)-3x=\frac{3}{4}x-3x-\frac{1}{2}-3x\\\\=\left(\frac{3}{4}-3-3\right)x-\frac{1}{2}=\boxed{-5\frac{1}{4}x-\frac{1}{2}}$

22. The least likely team to make the championship game is the one with the lowest probability.

3/8 < 1/2 < 2/3 < 4/5

The Bulldogs are least likely to play in the championship game.

4 0

3 years ago

Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y

I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

$\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }$