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Mamont248 [21]
3 years ago
8

Which is the better unit price: $1.99 for a 3-ounce bottle or $2.49 for a 4-ounce bottle?

Mathematics
2 answers:
Alex17521 [72]3 years ago
7 0

Answer:

The second option, $2.49 for a 4-ounce bottle.

Step-by-step explanation:

For the first option:

$1.99 for 3 ounces.

For 1 ounce,

1.99  \div 3 = 0.66333...

For the second option:

$2.49 for 4 ounces.

For 1 ounce,

2.49  \div 4 = 0.6225

Since 0.6225 is cheaper/less than 0.6633..., the second option is better as you can get one ounce at a cheaper rate.

notka56 [123]3 years ago
3 0

Answer:

2.49

Step-by-step explanation:

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Factorization of <br>x²+6x+5​
crimeas [40]

Answer:

(x +1) (x + 5)

Step-by-step explanation:

Factorization of x²+6x+5​

To factorise this quadratic expression we'll find 2  factors of 5 that when added gives the coefficient of x which is

Factors = +1 and +5

Sum = +6, product = +5

Rewriting equation

x² + x + 5x + 5

Factorising

x ( x +1) +5 ( x + 1)

(x +1) (x + 5)

I hope this was helpful, please mark as brainliest

7 0
3 years ago
HELP Please I will mark brainliest
Anit [1.1K]

Answer:

7.701

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which two points in the graphed function have an average rate of change of 5?
photoshop1234 [79]

First of all, a positive average rate of change means that the function is increasing, so the answer can only be A->B or B->C.

The average rate of change is defined as

A = \dfrac{f(b)-f(a)}{b-a}

i.e. as the ratio between the vertical and horizontal gain.

In order to go from point A to point B, you gain 1 unit horizontally and 5 units vertically. So, the average rate of change is 5/1=5.

In order to go from point B to point C, you gain 1 unit horizontally and 3 units vertically. So, the average rate of change is 3/1=3.

6 0
3 years ago
Please help
bezimeni [28]

Answer:

26-4s=9s

26-(4s-9s)=0

26+5s=0

5s=-26

ans: s= -26/5

-3r+10=15r-8

-3r-15r=-8-10

-18r=-18

18r=18

ans: r=1

-9(t-2)=4(t-15)

-9t+18=4t-60

-9t-4t=-60-18

-13t=-78

13t=78

ans: t=26

THERE U GO! :D

5 0
2 years ago
Read 2 more answers
Find the volume of a trough 5 meters long whose ends are equilateral triangles, each of whose
yawa3891 [41]

Answer:

V=5\sqrt{3}\ m^3

Step-by-step explanation:

we know that

The volume of a trough is equal to

V=BL

where

B is the area of equilateral triangle

L is the length of a trough

step 1

Find the area of  equilateral triangle B

The area of a equilateral triangle applying the law of sines is equal to

B=\frac{1}{2} b^{2} sin(60\°)

where

b=2\ m

sin(60\°)=\frac{\sqrt{3}}{2}

substitute

B=\frac{1}{2}(2)^{2} (\frac{\sqrt{3}}{2})

B=\sqrt{3}\ m^{2}

step 2

Find the volume of a trough

V=BL

we have

B=\sqrt{3}\ m^{2}

L=5\ m

substitute

V=(\sqrt{3})(5)

V=5\sqrt{3}\ m^3

3 0
4 years ago
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