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Mamont248 [21]
3 years ago
8

Which is the better unit price: $1.99 for a 3-ounce bottle or $2.49 for a 4-ounce bottle?

Mathematics
2 answers:
Alex17521 [72]3 years ago
7 0

Answer:

The second option, $2.49 for a 4-ounce bottle.

Step-by-step explanation:

For the first option:

$1.99 for 3 ounces.

For 1 ounce,

1.99  \div 3 = 0.66333...

For the second option:

$2.49 for 4 ounces.

For 1 ounce,

2.49  \div 4 = 0.6225

Since 0.6225 is cheaper/less than 0.6633..., the second option is better as you can get one ounce at a cheaper rate.

notka56 [123]3 years ago
3 0

Answer:

2.49

Step-by-step explanation:

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Lorico [155]
D = sqrt(3s^2) where s is the length of the side. Solving for s, 

<span>3s^2 = d^2 iff </span>
<span>s^2 = d^2 / 3 iff </span>
<span>s = sqrt(d^2 / 3) </span>
<span>= d / sqrt(3) or d sqrt(3) / 3 </span>

<span>Surface area of the cube = 6 s^2. Thus, </span>
<span>A = 6 (d / sqrt(3))^2 </span>
<span>= 6d^2 / 3 </span>
<span>= 2d^2 </span>

<span>Volume = s^3. Thus, </span>
<span>V = (d / sqrt(3))^3 </span>
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8 0
3 years ago
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Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 51% chan
Charra [1.4K]

Answer:

a) 0.3270 = 32.70% probability that Christine fails the course

b) 0.3917 = 39.17% probability that she had found someone to help

Step-by-step explanation:

We have these following probabilities:

61% probability that Christine find a coach.

100 - 61 = 39% probability that Christine does not find a coach.

With a coach, a 21% probability of failing.

Without a coach, a 51% probability of failing.

a. What is the probability that Christine fails the course?

21% of 61%(finds a tutor) plus 51% of 39%(does not find a tutor). So

P = 0.21*0.61 + 0.51*0.39 = 0.327.

0.327 = 32.7% probability that Christine fails the course

b. Christine ends up failing the course. What is the probability that she had found someone to help?

This can be formulated by the Bayes formula:

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening given that A happened and P(A|B) is the probability of A happening given that B happened.

In this question.

P(B|A) is the probability of finding a tutor given that she failed.

P(B) is the probability of finding a tutor. So P(B) = 0.61.

P(A|B) is the probability of failing when finding a tutor. So P(A|B) = 0.21

P(A) is the probability of failing. So P(A) = 0.327.

So

P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.61*0.21}{0.327} = 0.3917

0.3917 = 39.17% probability that she had found someone to help

4 0
3 years ago
I need help with this Adding Fractions problem. If you answer and fill out this whole page I will love you for the rest of my li
zhannawk [14.2K]

Answer:

omigosh hope she gets better i will look at the pdf and solve

Step-by-step explanation:

okay so for most of them you can just multiply by the denominator to turn it into a regular number (to get it out of fraction form) and then use basic algebra to solve for x. I 'll write the answers to problems 1-9 in the comments

8 0
3 years ago
Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.
Zigmanuir [339]
The mean is the average.
So, to find the mean you want o add up all of the numbers and then divide by the number of numbers.

49 + 49 + 54 + 55 + 52 + 49 + 575 = 363
363 / 7 = 51.85
Rounded to 52

For the median you want o line all of your number up from least to greatest and then find the middle number.

49,49,49,52,54,55,55

Your median is 52

The mode is the number that is listed most often

49 is listed 3 times
54 is listed 1 time
52 is listed 1 time
55 is listed 2 times

So, your mode is 49




4 0
3 years ago
Is this right? I feel like I’m wrong.
Arisa [49]

Answer:

no I believe you are correct

Hope This Helps! Have A Nice Day!!

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