All categories

3 years ago

Please help me with numbers 1 & 2. Please show work, thank you.

Mathematics

2 answers:

Orlov [11]3 years ago

7 0

1.) Jarvis lives 3 miles away from Cassidy and Theo lives 6 miles away.
(if Jarvis lives 3 miles away from Cassidy and Theo is twice as far from Jarvis, Theo would be twice as many miles away from Cassidy than Jarvis; 3 times 2 is 6; 3+6+=9)
2.) Jorge's watering can can hold 8 cups of water.
(Older brother's can hold 16 cups; 8+8+16= 32; there are 32 cups in 2 gallons)

Evgen [1.6K]3 years ago

3 0

1. 9 miles 2. 10 gallons and cups

You might be interested in

Y=2x-4 What is the five ordered pairs and completing the input/output table

kati45 [8]

Answer:

{(0, -4), (1, -2), (2, 0), (3, 2), (4, 4)}

Input values (x) = {0, 1, 2, 3, 4}

Output values (y) = {-4, -2, 0, 2, 4}

Step-by-step explanation:

Given the linear equation, y = 2x - 4, you could practically choose any input value (for x), to have an output value (for y).

If x = 0:

y = 2(0) - 4

y = 0 - 4

y = -4

First ordered pair: y-intercept = (0, -4)

If x = 1:

y = 2(1) - 4

y= 2 - 4

y = -2

Second ordered pair: (1, -2).

If x = 2:

y = 2(2) - 4

y= 4 - 4

y = 0

Third ordered pair: x-intercept = (2, 0).

If x = 3:

y = 2(3) - 4

y = 6 - 4

y = 2

Fourth ordered pair: (3, 2).

If x = 4:

y = 2(4) - 4

y = 8 - 4

y = 4

Fifth ordered pair: (4, 4).

Your input values (x) = {0, 1, 2, 3, 4}

Your output values (y) = {-4, -2, 0, 2, 4}

6 0

3 years ago

Lucy drove 300 miles in 10 hours. On average, how fast did she drive in hours per

Simora [160]

Answer: 30 miles per hour

Step-by-step explanation:

Speed = distance / time

= 300 / 10

= 30 miles per hour

7 0

3 years ago

James Middle School, 500 students were asked their favorite sport to watch on TV 35% of the students like watching basketball 15

Anni [7]

I don’t get this so I can’t help with this is a hard answer

5 0

3 years ago

) a, p and d are n×n matrices. check the true statements below:

BigorU [14]

A. False. Consider the identity matrix, which is diagonalizable (it's already diagonal) but all its eigenvalues are the same (1).

b. True. Suppose $\mathbf P$ is the matrix of the eigenvectors of $\mathbf A$ , and $\mathbf D$ is the diagonal matrix of the eigenvalues of $\mathbf A$ :

$\mathbf P=\begin{bmatrix}\mathbf v_1&\cdots&\mathbf v_n\end{bmatrix}$

$\mathbf D=\begin{bmatrix}\lambda_1&&\\&\ddots&\\&&\lambda_n\end{bmatrix}$

Then

$\mathbf{AP}=\begin{bmatrix}\mathbf{Av}_1&\cdots&\mathbf{Av}_n\end{bmatrix}=\begin{bmatrix}\lambda_1\mathbf v_1&\cdots&\lambda_n\mathbf v_n\end{bmatrix}=\mathbf{PD}$

In other words, the columns of $\mathbf{AP}$ are $\mathbf{Av}_i$ , which are identically $\lambda_i\mathbf v_i$ , and these are the columns of $\mathbf{PD}$ .

c. False. A counterexample is the matrix

$\begin{bmatrix}1&1\\0&1\end{bmatrix}$

which is nonsingular, but it has only one eigenvalue.

d. False. Consider the matrix

$\begin{bmatrix}0&1\\0&0\end{bmatrix}$

with eigenvalue $\lambda=0$ and eigenvector $\begin{bmatrix}k&0\end{bmatrix}^\top$ , where $k\in\mathbb R$ . But the matrix can't be diagonalized.

7 0

3 years ago

I WILL AWARD BRAINLIEST!! Find the value of x in each case.

fredd [130]

See the attached picture for the solution:

6 0

3 years ago

Read 2 more answers