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yaroslaw [1]
3 years ago
15

Please help me with numbers 1 & 2. Please show work, thank you.

Mathematics
2 answers:
Orlov [11]3 years ago
7 0
1.) Jarvis lives 3 miles away from Cassidy and Theo lives 6 miles away.
(if Jarvis lives 3 miles away from Cassidy and Theo is twice as far from Jarvis, Theo would be twice as many miles away from Cassidy than Jarvis; 3 times 2 is 6; 3+6+=9)
2.) Jorge's watering can can hold 8 cups of water.
(Older brother's can hold 16 cups; 8+8+16= 32; there are 32 cups in 2 gallons)
Evgen [1.6K]3 years ago
3 0
1. 9 miles 2. 10 gallons and cups
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Please help me out with this!!
galina1969 [7]

Answer:

see explanation

Step-by-step explanation:

Given

x + \frac{1}{2} ≤ - 3 or x - 3 > - 2

Solve the left and right inequalities separately, that is

x + \frac{1}{2} ≤ - 3 ( isolate x by subtracting \frac{1}{2} from both sides )

x ≤ - 3 - \frac{1}{2}, that is

x ≤ - \frac{6}{2} - \frac{1}{2}, thus

x ≤ - \frac{7}{2}

OR

x - 3 > - 2 ( isolate x by adding 3 to both sides )

x > 1

Solution is

x ≤ - \frac{7}{2} or x > 1

7 0
3 years ago
Forgot to do this over winter break. Its due tomorrow and I haven't used my brain for 2 weeks. HELPPP (may have to zoom in)
ANEK [815]
1. 60,30,90 right triangle. y will be hypotenuse/2, x will be
hypotenuse*sqrt(3)/2. So x = 16*sqrt(3)/2 = 8*sqrt(3), approximately 13.85640646 
y = 16/2 = 8  
2. 45,45,90 right triangle (2 legs are equal length and you have a right angle).
X and Y will be the same length and that will be hypotenuse * sqrt(2)/2. So 
x = y = 8*sqrt(2) * sqrt(2)/2 = 8*2/2 = 8 
 3. Just a right triangle with both legs of known length. Use the Pythagorean theorem 
x = sqrt(12^2 + 5^2) = sqrt(144 + 25) = sqrt(169) = 13  
4. Another right triangle with 1 leg and the hypotenuse known. Pythagorean theorem again. 
y = sqrt(1000^2 - 600^2) = sqrt(1000000 - 360000) = sqrt(640000) = 800  5. A 45,45,90 right triangle. One leg known. The other leg will have the same length as the known leg and the hypotenuse can be discovered with the Pythagorean theorem.  x = 6. y = sqrt(6^2 + 6^2) = sqrt(36+36) = sqrt(72) = sqrt(2 * 36) = 6*sqrt(2), approximately 8.485281374  
6. Another 45,45,90 triangle with the hypotenuse known. Both unknown legs will have the same length. And Pythagorean theorem will be helpful. 
x = y. 
12^2 = x^2 + y^2 
12^2 = x^2 + x^2 
12^2 = 2x^2 
144 = 2x^2 
72 = x^2 
sqrt(72) = x 
6*sqrt(2) = x 
x is approximately 8.485281374  
7. A 30,60,90 right triangle with the short leg known. The hypotenuse will be twice the length of the short leg and the remaining leg can be determined using the Pythagorean theorem. 
y = 11*2 = 22. 
x = sqrt(22^2 - 11^2) = sqrt(484 - 121) = sqrt(363) = sqrt(121 * 3) = 11*sqrt(3). Approximately 19.05255888  
8. A 30,60,90 right triangle with long leg known. Can either have fact that in that triangle, the legs have the ratio of 1:sqrt(3):2, or you can use the Pythagorean theorem. In this case, I'll use the 1:2 ratio between the unknown leg and the hypotenuse along with the Pythagorean theorem. 
x = 2y 
y^2 = x^2 - (22.5*sqrt(3))^2 
y^2 = (2y)^2 - (22.5*sqrt(3))^2 
y^2 = 4y^2 - 1518.75 
-3y^2 = - 1518.75 
y^2 = 506.25 = 2025/4 
y = sqrt(2025/4) = sqrt(2025)/sqrt(4) = 45/2 
Therefore: 
y = 22.5
 x = 2*y = 2*22.5 = 45  
9. Just a generic right triangle with 2 known legs. Use the Pythagorean theorem. 
x = sqrt(16^2 + 30^2) = sqrt(256 + 900) = sqrt(1156) = 34  
10. Another right triangle, another use of the Pythagorean theorem. 
x = sqrt(50^2 - 14^2) = sqrt(2500 - 196) = sqrt(2304) = 48
8 0
3 years ago
Jackson's rectangular orchard is 6 km long and 4 km wide.    What is the area of Jackson's orchard?
Levart [38]
For a rectangle area, use base x height, or length x width.


6 km long x 4 km wide = 24 km 

The area of Jackson's orchard is 24 km

hope this helps

x = multiply
5 0
3 years ago
Need help ASAP!!!!!
svetlana [45]

Answer:

cos 45 degree = A/H

cos 45 degree =  2 square root 2 / x

x = 2 square root 2 / cos 45 degree

x = 4

Sin 45 degree = O/H

Sin 45 degree = y/ 4

4 x Sin 45 degree = y

y = 2.83

or

we could use tan

tan 45 degree = O/A

tan 45 degree = y / 2 square root 2

2 square root 2 x tan 45 degree = y

y = 2.83

i hope this would elp a little bit.

3 0
3 years ago
In numbers 8 & 9, graph f(x). Show all asymptotes and/or holes, x- & y-intercepts, and end
SCORPION-xisa [38]

Answer:

8fx=;x2-7x+12;x-4;6

Step-by-step explanation:

x2"   was replaced by   "x^2".

7 0
3 years ago
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