Which number line shows the solutions to x > 5?

Mathematics

2 answers:

Montano1993 [528]2 years ago

8 0

D I think so, I might be wrong tho

snow_tiger [21]2 years ago

4 0

The answer is D i hope you do a great job

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A candidate scored 32 marks out of 80,

Verizon [17]

Answer:

40%

Step-by-step explanation:

you need to divide 80 by 8 to get 10 and then divide 32 by 8 aswell. this gives you 4/10 which is equivalent to 40/100 or 40%

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3 years ago

5 to the fourth power times (5 to the negative 3rd power) and 2

VARVARA [1.3K]

What does the and 2 mean? Does it mean times two or plus two?

Step-by-step explanation:

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3 years ago

A bag contains $3$ white chips and $3$ red chips. you repeatedly draw a chip at random from the bag. if it's white, you set it a

Natasha2012 [34]

Answer:

8.5

Step-by-step explanation:

We can divide this experiment in three parts.

Before removing any white chip
After ramoving one white chip, and before removing two
After removing two white chips

For the first experiment, for each extraction we will always have 3 white chips and 3 red chips, becuase if we extract a red chip, then we put it back in the bag, and if it is a white chip, then the experiment ends there. The probability of taking out a white chip is 1/2.

For the second experiment, we will have always 2 white chips, and 3 red chips. So the probability of success is 2/5 = 0.4

For the third experiment, we will have always 1 white chip and 3 red chips, so the probability of success if 1/4 = 0.25.

We want to know how many extractions we need for each experiment until we pick a white chip. Note that each experiment is independent of each other, and each one has geometric distribution, the first one with probability of success 0.5, the second one with probability of success 0.4, and the third one with p = 0.25.

The total experiment, X, is the sum of this random variables, so the expected value of the total experimet is the sum of the expected value from each of its parts, lets call them, X₁, X₂ and X₃. Thus,

$E(X) = E(X_1) + E(X_2) + E(X_3) = \frac{1}{0.5}+\frac{1}{0.4} +\frac{1}{0.25} = 2 + 2.5 + 4 = 8.5$