For this problem, I'd use cross-multiplication.
9/12 = x/8.
When cross multiplying, multiply 12*x and 9*8. This leads to a new equation:
12x = 72.
Then you solve as an algebra problem.
*Divide 12 on both sides*
x = 6.
Given :
Length of parade , 
.
Breadth of parade , 
.
5 people can fit into a 
area.
1 mile = 5280 ft .
To Find :
The size of the crowd.
Solution :
Area of parade ,
Also , 5 people can fit in area .
So , number of people fit in A is :
Therefore , 95040 can fit in the parade .
Hence , this the required solution .
We will need to find the perimeter here, since in this context we’re talking about fencing around a rectangular pool. The formula for perimeter is P = 2L + 2W. The L and W can stand for length/width which is the same as wide/long in this problem. I will now plug in the numbers. P = 2(38) + 2(20) which gives us 76 + 40. 76 + 40 is 116. Therefore, the perimeter is 116 ft.
I know that the fencing company charges $22 per foot. I can multiply 116 x 22 to give me $2552. The answer is $2552.
