How many degrees are in the sum of the interior and exterior angles of a polygon having 5 sides?
1 answer:
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Answer: 3.217 & 12.434
Step-by-step explanation:
If we use <em>w</em> to represent the width, the length will be 6 more than 2 times w.
Hence, the length is .
The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.
We can also substitute 40 in for A as it's given in the question.
Distributing <em>w</em> by multiplying it by both terms in the parentheses, we get
We can make the equation simpler by dividing both sides by 2.
Subtracting both sides by 20 will make the left-hand side 0.
Now that we have put this <em>quadratic equation</em> into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.
For reference, the quadratic formula is
In this case, a is 1, b is 3, and c is -20.
Substituting, we get
Since the second solution results in a negative number, it cannot be the length of w.
The width/breadth of the rectangle is 3.217 cm.
To calculate the length, let's substitute the width into the expression for the length:
The length of this rectangle is 12.434 cm.
Answer:
Area of Trapezoid is 39 unit²
Step-by-step explanation:
Given as :
For A Trapezoid
The measure of base side 1 = = 10 unit
The measure of base side 2 = = 16 unit
The height of the Trapezoid = h = 3 unit
Let The Area of Trapezoid = A square unit
<u>Now, From Formula</u>
Area of Trapezoid = × (sum of opposite base) × height
I.e A = × (
+
) × h
Or, A = × (10 unit + 16 unit) × 3 unit
Or, A = × (26 unit) × 3 unit
Or, A = × 78 unit²
Or, A = unit²
I.e A = 39 unit²
So, The Area of Trapezoid = A = 39 unit²
Hence, The Area of Trapezoid is 39 unit² . Answer