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3 years ago

If a pentagon has a radius of 16 find the perimeter

Mathematics

1 answer:

nignag [31]3 years ago

8 0

Answer:

94.05 units is the perimeter of this pentagon.

Length of each side in pentagon: 2r × Sin(180/n)

where r is radius and n is number of sides

Using the formula: 2r × Sin(180/n)

: 2*16 * sin(180/5)

: 18.8 units

Perimeter = 5(18.8) units........5 as we know pentagon has 5 sides

= 94.05 units

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Slope = 4/1 = 4

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3 years ago

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Translate to a proportion and solve. 148.5 is 59 1/5% of what?

lesantik [10]

The actual value is 250.84 .

Formula

Percentage calculation =(given value/total value)*100

let the actual value is "x"

percentage we known is 59 1/5% (59.2%) and 59.2% of x is 148.5.

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x=(148.5/59.2)*100

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The actual value is 250.84 .

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2 years ago

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3 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD=√2 cm.

Zielflug [23.3K]

Given that triangle ABC is right angle triangle. CD is altitude such that AD=BC

ABC is a right angle triangle so apply Pythogorean theorem

$AC^{2} + BC^{2} = AB^{2}$

$AC^{2} + AD^{2} = AB^{2}$ (Given that AD = BC)

$AC^{2} + AD^{2} = 3^{2}$ (Given that AB=3)

$AC^{2} + AD^{2} = 9$ ...(i)

ADC is a right angle triangle so apply Pythogorean theorem

$AD^{2} + CD^{2} = AC^{2}$

$AD^{2}+(\sqrt{2})^2= AC^{2}$

$AD^{2}+2= AC^{2}$

$AD^{2}=AC^{2} -2$ ...(ii)

Plug value (ii) into (i)

$AC^{2} + AC^{2}-2 = 9$

$2AC^{2} -2=9$

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$AC^{2} =\frac{11}{2}$

$AC=\sqrt{\frac{11}{2} }$

Hence final answer is $AC=\sqrt{\frac{11}{2} }$

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