What is 40.53 ounces converted to liters?

umka2103 [35]

Answer:

1 - (π/6) - (√3/4)

Step-by-step explanation:

First, calculate the area of ABCD. That's just $1*1 = 1 un^{2}$

Then, we are told that arcs BD and AC are circular, meaning they are portions of a circle. Therefore, let's redraw this image a little. Look below for the image.

Essentially, what I've done is created an equilateral triangle and two sectors. You may be wondering why the triangle is equilateral. Well, we firstly know it's isosceles because the two original arcs are circular and congruent. Their overlap creates two congruent lines that can be extend from point M to the vertices A and D. These two lines also happen to be radii of the quarter circles because the two sectors have AM AND AD as radii. AM and AD = 1, so AMD is an equilateral triangle.

Draw altitude OD. This is a right angle. Since equilateral triangles are also isosceles triangles, and isosceles triangles have the property of sharing the median to base and altitude to base, we can say that OD = $\frac{1}{2}$ AD = $\frac{1}{2}$ . MD = 1, so this triangle is a 30-60-90 triangle. Why? This is because of the 30º angle converse theorem. The shorter leg is half of the hypotenuse MD, so <OMD is a 30º angle, making <ODM a 60º angle and inevitably <MDC a 30º angle (because <D is a right angle) and <ABM as well because the two sectors are congruent.

Because m<ABM = m<MDC = 30º, these two sectors are 30/360 of the individual circles or 1/12 of the original circles, which have areas of π (because 1^2*π = π). Each is 1/12π, combined they are 1/6π.

The area of the equilateral triangle is √3/8. This is because MO can be calculated, using the 30-60-90 ratios, to be √3/2. (1 * √3/2)/2 = (√3/2)/2 = √3/4; this uses the area of a triangle. Now, time to calculate the shaded area.

The area of the square is 1, the area of the sectors π/6, and the equilateral triangle √3/4. Subtract the equilateral triangle and sectors' areas from the area of the square to be left with the remaining shaded part. 1-(π/6)-(√3/4) is your final answer. To put that a little more cleanly below in the image.

Hope this helps, have a great day.

3 0

2 years ago

Sandrena and her friends brought frozen yogurt for 55 cents per ounce.their total was $10.45.how many ounces did they buy?

lianna [129]

You would divide 10.45 by .55 and you would get 19 so 19 is your answer hope this helps

6 0

3 years ago

The diagram shows an equilateral triangle, a square, and one diagonal of the square. what is the value of x

Verizon [17]

Answer:

can u get a pic of the diagram

Step-by-step explanation:

4 0

2 years ago

How to graph -5\3 on a number line

Alex_Xolod [135]

<span>Number line is a way of expressing an integer into a line.
We have the given numbers:
Let x = -5
and Let y = 3

Now let’s create line with 0 in the center. Pls. see the attached image for the number line presentation.

The answer is -2</span><span>

</span>

8 0

3 years ago

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow

kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

$H_0: \mu = 13252$

At the alternative hypothesis, we test if the mean cost has increased, that is:

$H_1: \mu > 13252$

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that $\mu = 13252$

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that $n = 20, X = 15560, s = 3500$

Value of the test statistic:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}$

$t = 2.95$

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

7 0

2 years ago