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Stels [109]
2 years ago
15

Hurry and graph this please

Mathematics
1 answer:
lutik1710 [3]2 years ago
4 0
Function 1
Domain- all real numbers
Root: (3,0)
Range: all real numbers
Vertical intercept: (0,6)

Function 2
Root: (8,0)
Range: all real numbers
Vertical intercept: (0,6)
Domain: all real numbers

Solution:(4,-2)
(X,y)
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The letter​ "t" makes up an estimated 10​% of a certain language. Assume this is still correct. A random sample of 500 letters i
Andrew [12]

Answer:

  0.2755

Step-by-step explanation:

We intend to make use of the normal approximation to the binomial distribution.

First we'll check to see if that approximation is applicable.

For p=10% and sample size n = 500, we have ...

  pn = 0.10(500) = 50

This value is greater than 5, so the approximation is valid.

__

The mean of the distribution we'll use as a model is ...

  µ = p·n = 0.10(500)

  µ = 50

The standard deviation for our model is ...

  σ = √((1-p)µ) = √(0.9·50) = √45

  σ ≈ 6.708204

__

A continuity correction can be applied to better approximate the binomial distribution. We want p(t ≤ 9.1%) = p(t ≤ 45.5). For our lookup, we will add 0.5 to this limit, and find p(t ≤ 46).

The attached calculator shows the probability of fewer than 45.5 t's in the sample is about 0.2755.

6 0
3 years ago
which equation would help you solve this problem? there are 18 muffins on a plate. if they are split equally among 9 people, how
cluponka [151]
They would each get 1 muffin ( 18/9=2)
3 0
3 years ago
Given P(A) = 0.072, P(B) = 0.180, and P(C) = 0.027, and that events A, B, and C are mutually exclusive, what is the P(A or B or
9966 [12]

Given P(A) = 0.072, P(B) = 0.180, and P(C) = 0.027, and that events A, B, and C are mutually exclusive,then P(A or B or C) is 0.279

<u>Solution: </u>

Given that probability of event A is P(A) = 0.072

Probability of event B is P(B) = 0.180

Probability of event C is P(C) = 0.027

Also event A, B and C are mutually exclusive.

Need to determine P( A or B or C )

For mutually exclusive events  

P( A or B or C ) = P(A) + P(B) + P(C)

= 0.072 + 0.180 + 0.027  = 0.279

Hence probability of occurrence of event A or event B or event C , where A , B and C are mutually exclusive events is 0.279.

5 0
3 years ago
Help me pls fast ASAP
lidiya [134]

Um... I beleive its A due to 2x times 3x with an exponet of 2 would make 6x with the exponet of 2 then you would add 5

8 0
3 years ago
Code Namo
Cerrena [4.2K]

Answer:

Step-by-step explanation:

5 0
3 years ago
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