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astra-53 [7]
3 years ago
8

The value of x and the value of y

Mathematics
2 answers:
egoroff_w [7]3 years ago
7 0

Answer:

x= 60 y=50

Step-by-step explanation:

First to find x, all the degrees in a triangle add up to 180 degrees. So 50+70+x=180 which is also 120+x=180 which means x=60. Y is the exterior angle of x and a missing angle. Let's substitute the missing angle with the variable z. 60+50+z=180 which is 110+z=180 which means z is 70. So 180-x+z=y. 180-60+70=y which means y is equal to 50. Hope this helps!

lianna [129]3 years ago
5 0
X=60
y=50
a triangle is 180° so if you subtract 70 and 50 from that you get 60=x
a straight line is also 180° so use the same method above from the left triangle and subtract all from 180 to get y
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a) 0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

b) 0.2693 = 26.93% probability that this drug user never used the prohibited drug.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

A. If an athlete is selected at random, what is the probability that athlete will test positive for prohibited drug use?

100 - 5 = 95% of 8%

100 - 13 = 87% of 17%

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p = 0.95*0.08 + 0.87*0.17 + 0.11*0.75 = 0.3064

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

B. If an athlete tests positive after a drug test, what is the probability that this drug user never used the prohibited drug?

Conditional Probability

Event A: Tests Positive

Event B: Never used the drug.

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use

This means that P(A) = 0.3064

Probability of testing positive while never using the drug.

11% of 75%. So

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P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0825}{0.3064} = 0.2693

0.2693 = 26.93% probability that this drug user never used the prohibited drug.

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3 years ago
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