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3 years ago

6

A fire fighter truck can hold 3000 gallons of water a firefighter can deliver 160 gallons of water every two minutes how long wi

ll it take for the firefighter to empty the truck

1 answer:

Ugo [173]3 years ago

5 0

Answer:

18.75

Step-by-step explanation:

just divide 3000 by 160 which is 18.75.

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What is <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20-7%3D%5Csqrt%7Bx%20-7" id="TexFormula1" title="\sqrt{x} -7=\sqrt{x -7

chubhunter [2.5K]

USE PHOTOMATH , it will solve it and show you how to do it , I use it for maths questions like this !!!!!!

3 0

3 years ago

What is 6(m + 4) =_m +_

Zielflug [23.3K]

Answer:

6m+24

Step-by-step explanation:

basically you multiply m and 4 by six soooo

6 times m is 6x

6 times 4 is 24

soo

6m+24 is correct

can i have rainliest pleaseee:)b

5 0

3 years ago

Will give brainliest!!

vivado [14]

Answer:

continuous.

Step-by-step explanation:

Given function is $f(x)=5x^4-9x^3+x-7$ .

and value of a = 7.

Now we need to find if the given function $f(x)=5x^4-9x^3+x-7$ is continuous or not.

By definition of continuity, we know that a function is continuous at a given point if both left and right hand limits are equal.

Left Hand Limit = LHL

$LHL=\lim_{x\rightarrow 7^-}f(x)=5(7)^4-9(7)^3+(7)-7=8918$

Right Hand Limit = RHL

$RHL=\lim_{x\rightarrow 7^+}f(x)=5(7)^4-9(7)^3+(7)-7=8918$

Since both limits are equal at a=7 so we can say that given function is continuous at a=7

4 0

3 years ago

Infinite Algebra 2

Irina-Kira [14]

The first problem, all you need to do is combine like terms then isolate the n:
4n-2n=4
~subtract 2n from 4n (2n)
2n=4
~then divide both sides of the equation by 2 to isolate the n
n=4

The second problem follows the same steps of combining like terms and isolating the variable. Here, you'll have to combine 2 like terms:
-12=2+5v+2v
~first combine the variables which is just 5v+2v which is 7v
-12=2+7v
~then subtract 2 from both sides to isolate the 7v
-14=7v
~then divide both sides by 7 to isolate the v and get your answer
-2=v

Hope that helped!

4 0

3 years ago

A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is

scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=360000$ represent the mean for the downtown restaurant

$\bar X_{2}=340000$ represent the mean for the freeway restaurant

$s_{1}=50000$ represent the sample standard deviation for downtown

$s_{2}=40000$ represent the sample standard deviation for the freeway

$n_{1}=36$ sample size for the downtown restaurant

$n_{2}=36$ sample size for the freeway restaurant

t would represent the statistic (variable of interest)

$\alpha=0.05$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis: $\mu_{1}\leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level $\alpha=0.05$ and $\alpha/2=0.025$ we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is $t_{1-\alpha/2}=1.66$

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874$

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

$p_v =P(t_{70}>1.874)=0.033$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0

3 years ago