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LekaFEV [45]
2 years ago
8

Section 5.2 Problem 17:

Mathematics
1 answer:
Elina [12.6K]2 years ago
8 0

This DE has characteristic equation

4r^2 - 12r + 9r = (2r - 3)^2 = 0

with a repeated root at r = 3/2. Then the characteristic solution is

y_c = C_1 e^{\frac32 x} + C_2 x e^{\frac32 x}

which has derivative

{y_c}' = \dfrac{3C_1}2 e^{\frac32 x} + \dfrac{3C_2}2 x e^{\frac32x} + C_2 e^{\frac32 x}

Use the given initial conditions to solve for the constants:

y(0) = 3 \implies 3 = C_1

y'(0) = \dfrac52 \implies \dfrac52 = \dfrac{3C_1}2 + C_2 \implies C_2 = -2

and so the particular solution to the IVP is

\boxed{y(x) = 3 e^{\frac32 x} - 2 x e^{\frac32 x}}

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