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azamat
2 years ago
10

Is this graph a function or not a function?

Mathematics
1 answer:
weeeeeb [17]2 years ago
4 0

Answer:

It is a function.

Step-by-step explanation:

You can test if a graph is a function if you draw a vertical line anywhere on the graph and you see it hits two points.

This is the table for the graph.

\left[\begin{array}{ccc}x&y\\-3&0\\0&1\\3&2\end{array}\right]

Remember these rules:

  • Each x value, or input, has its unique y value, or output
  • If you draw a vertical line anywhere on the graph, it should only go through one point

We can check these two rules for this graph:

  • Does each x value have its own, unique y value? Yes
  • If you draw a vertical line anywhere on the graph, does it only go through one point? Yes, there are no overlaps

Keep in mind that two different x-values can have the same y value.

Figure 1:

It has two x values with the same y-values.

Figure 2 and 3:

The vertical line goes through two points. So the same x-value has two different y-values.

-Chetan K

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Step-by-step explanation:

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3 years ago
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Tems11 [23]

Answer:

a) 8.13

b) 4.10

Step-by-step explanation:

Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1

In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)

On integrating R'(t)

∫ (2/t+1 + 1/√t+1)dt

In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.

∫ (2/t+1 + 1/√t+1)dt

= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt

= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt

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= 2ln(t+1) + 2√(t+1) + C

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When t = 1

R(1) = 2ln2 + 2√2

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When t = 12

R(12) = 2ln13 + 2√13

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R(12) - R(1) ≈ 12.34-4.21

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Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.

b) For total reactions from t = 12 to t = 24

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

When t = 24

R(24) = 2ln25 + 2√25

≈ 16.44

R(12) - R(1) ≈ 16.44-12.34

≈ 4.10

Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10

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Answer:

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