Answer:
Step-by-step explanation:
S=θ/360*2πr
S=0.020943951r

<u>Given expression is </u>

can be rewritten as

We know,

And

So, using this identity, we


can be further rewritten as





<u>Hence, </u>

Answer:
I'll explain below, just follow the directions. I can't directly draw it.
Step-by-step explanation:
find the length and the width of a rectangle whose perimeter is 18 ft
2L + 2W = 18
simplify, divide by 2
L + W = 9
L = (9-W)
:
whose area is 20 square feet
L*W = 20
Replace L with (9-W)
W(9-W) = 20
-W^2 + 9W - 20 = 0
Multiply by -1, easier to factor
W^2 - 9W + 20
Factors to
(W-4)(W-5) = 0
Two solutions
W = 4 ft is width, then 5 ft is the Length
and
W = 5 ft is the width, then 4 ft
49*4=196+1=197/4
<span>8*3=24+3=27/8 </span>
<span>then make the denominator the same</span>
<span>multiply 197*2 and 4*2 = 394/8 </span>
<span>then 394/8 +27/8 =421/8 </span>
<span>u can either leave it here or in decimal form which would be 52.625 or in mixed numbers-52 5/8</span>