2 years ago

Similarity and altitudes in right triangles

Mathematics

1 answer:

Aleks04 [339]2 years ago

5 0

Answer: First I suggest that you write out the all the proportions which govern the 3 right triangles involved.

Once you do that you will find this one:

PQ/PS =PR/PQ

PR=PS+SR

Substitution will give you this quadratic:PQ2=PS2+PS*SR

144=PS2+7PS which has only one solution which make sense, namely 9

Then QS=sqrt(144-81)

Step-by-step explanation:

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