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seraphim [82]
2 years ago
7

Given the functions k(x) = 2x2 − 7 and p(x) = x − 4, find (k ∘ p)(x). (k ∘ p)(x) = 2x2 − 8x 16 (k ∘ p)(x) = 2x2 − 16x 32 (k ∘ p)

(x) = 2x2 − 16x 25 (k ∘ p)(x) = 2x2 − 11.
Mathematics
1 answer:
never [62]2 years ago
7 0

Function represents a relationship between variables. The product of the two given functions (k·p)(x) is 2x³-8x²-7x+28.

<h3>What is Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

Given to us

k(x) = 2x² − 7

p(x) = x − 4

As the two equations are given to us, k(x) and p(x), and we need to find (k ∘ p)(x), And we know the product of two functions can be written as,

(k \cdot p)(x) = k(x) \cdot p(x)

therefore,

k(x) \cdot p(x)\\\\= (2x^2-7)(x -4)\\\\= 2x^3 - 8x^2 - 7x +28

Hence, the product of the two given functions (k·p)(x) is 2x³-8x²-7x+28.

Learn more about Function:

brainly.com/question/5245372?referrer=searchResults

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Deffense [45]

Answer:

2 \div 3h - 1 \div 3  h+ 11 = 8 \\ 2 - 1 \div 3h =  - 3 \\ 1 \div 3h =  - 3 \\  - 9h = 1 \\ h =  - 1 \div 9

-1/9 is the answer

8 0
3 years ago
1. Determine the value of y, if x is 5 for the function y = x2 -9.
user100 [1]
Sub in 5 for x
y=(5)2 -9
y= 10-9
y= 1
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3 years ago
Whats is 4 hundreds 13 tens 5 ones in standard form
mars1129 [50]
<span>4 hundreds 13 tens 5 ones = 400+13*10+5
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3 years ago
PLZZ HELP Fill in the blank with the correct response. The slope of the graph of y = x is ___a0.
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y = x ← is in slope- intercept form

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6 0
3 years ago
2(x-6)+5=-5<br>75=27+3(3t-2)<br>-2/3(6c-9)+x=-18
anyanavicka [17]

Answer:

{c = 25/4

{t = 6

{x = 1

Step-by-step explanation:

Solve the following system:

{2 (x - 6) + 5 = -5 | (equation 1)

{75 = 3 (3 t - 2) + 27 | (equation 2)

{x - 2/3 (6 c - 9) = -18 | (equation 3)

Express the system in standard form:

{0 c+0 t+2 x = 2 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

{-(4 c) + 0 t+x = -24 | (equation 3)

Swap equation 1 with equation 3:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

0 c+0 t+2 x = 2 | (equation 3)

Divide equation 2 by -9:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+2 x = 2 | (equation 3)

Divide equation 3 by 2:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Subtract equation 3 from equation 1:

{-(4 c)+0 t+0 x = -25 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Divide equation 1 by -4:

{c+0 t+0 x = 25/4 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Collect results:

Answer: {c = 25/4

{t = 6

{x = 1

4 0
3 years ago
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