Answer:
The volume of the cone is 100.48 units³ approximately
Step-by-step explanation:
To find the volume of a cone with a diameter of 8 unit and height of 6 units, we will follow the steps below;
first, write down the formula for calculating the volume of a cone
v= πr²
where v is the volume of the cone
r is the radius and h is the height of the cone
from the question given, diameter d = 8 units but d=2r which implies r=d/2
r=8/2 = 4 units
Hence r= 4 units
height = 6 units
π is a constant and is ≈ 3.14
we can now proceed to insert the values into the formula
v= πr²
v ≈ 3.14 × 4² × 6/3
v ≈ 3.14 × 16 × 2
v ≈ 100 .48 units³
Therefore the volume of the cone is 100 .48 units³ approximately
Because the focus is (-2,-2) and the directrix is y = -4, the vertex is (-2,-3).
Consider an arbitrary point (x,y) on the parabola.
The square of the distance between the focus and P is
(y+2)² + (x+2)²
The square of the distance from the point to the directrix is
(y+4)²
Therefore
(y+4)² = (y+2)² + (x+2)²
y² + 8y + 16 = y² + 4y + 4 + (x+2)²
4y = (x+2)² - 12
y = (1/4)(x+2)² - 3
Answer:
Answer:
The answer to your question is the third histogram
Step-by-step explanation:
What we must check in a histogram is that the x-axis is represented the intervals and in the y-axis is represented the frequency.
The first histogram is incorrect just by observing the first bar, we notice that the correct frequency from 0 to 4 is 3, not 14. This histogram is incorrect.
Also, the second histogram is incorrect, the frequency of the first category is 3, not 12. This histogram is wrong.
The third histogram is correct because all the bars are in agreement with their frequencies.
The last histogram is incorrect, for example, the last frequency is 12, not 3.