Ask question

Ask question

All categories

professor190 [17]

2 years ago

7

4(12y+3)+y=12 _ + 12 + y = 12_ +12 = 12 49y = _ y = _

2 answers:

prisoha [69]2 years ago

6 0

The answer is 42 bc I really do not know trying to get points!

timama [110]2 years ago

3 0

4(12y+3)+y=12
48y+12+y=12
49y+12=12
-12 -12
49y=0
0/49=0
Y=0

You might be interested in

P = a + b +c for b what the answer math

Elena L [17]

Answer:

p - a - c = b

Step-by-step explanation:

p = a + b + c

subtract a and b from both sides to isolate c

p - a - c = a - a + b

+ c - c

3 0

3 years ago

Can anybody help me???

marysya [2.9K]

Answer:

Help you with what? their is nothing!

6 0

4 years ago

Read 2 more answers

Find the value of x in the triangle shown below

pantera1 [17]

Answer:

48 (i might be wrong)

Step-by-step explanation:

180-66-66=48

7 0

3 years ago

Use the definition of a derivative to find f’(x).

tatyana61 [14]

Answer:

f'(x) = $-\frac{9}{x^2}$

Step-by-step explanation:

i) f(x) = 9 / x

ii) f'(x) = $$\lim_{h\to 0} \frac{f(x+h) - f(x)}{h} $ \hspace{0.2cm}$

$= $\lim_{h\to 0} \frac{\frac{9}{x+h} - \frac{9}{x} }{h} = \hspace{0.1cm} $\lim_{h\to 0} \frac{9x - 9(x+h)}{hx(x+h)} $ \hspace{0.1cm} = \hspace{0.1cm}$\lim_{h\to 0} \frac{-9h}{hx(x+h)} = $\lim_{h\to 0} \frac{-h}{x(x+h)} = \frac{-9}{x^2}$$

7 0

3 years ago

Enter your answer and show all the steps that you use to solve this problem in the space provided. Find the values of x and y.

satela [25.4K]

Answer : The value of x and y is, $90^o$ and $43^oC$

Step-by-step explanation :

First we have to calculate the angle B.

As we know that,

The given triangle is an isosceles triangle in which the angles opposite to equal sides are always equal.

Thus, $\angle B=\angle C$

Given : $\angle C=47^o$

$\angle B=\angle C=47^o$

$\angle B=47^o$

Now have to calculate the angle A.

As we know that the sum of interior angles of a triangle is equal to $180^o$ .

$\angle A+\angle B+\angle C=180^o$

$\angle A+47^o+47^o=180^o$

$\angle A+94^o=180^o$

$\angle A=180^o-94^o$

$\angle A=86^o$

Now we have to determine the angle y.

As we know that, line AD is an angle bisector. That means, it divides into two equal angles. So,

$\angle y=\frac{\angle A}{2}$

$\angle y=\frac{86^o}{2}$

$\angle y=43^o$

Now we have to determine the angle x.

As we know that the sum of interior angles of a triangle is equal to $180^o$ .

$\angle y+\angle B+\angle x=180^o$

$43^oc+47^o+\angle x=180^o$

$\angle x+90^o=180^o$

$\angle x=180^o-90^o$

$\angle x=90^o$

Thus, the value of x and y is, $90^o$ and $43^oC$

6 0

3 years ago