If a shape is translated (has it's vertex' coordinates moved/changed), then it retains its original values but just has different vertex coordinates.
Thus since DE is equal to UV, then,
DE = UV; substitution:
5=5
Well this problem can be solved with Algebra
the rule here is that for every incrementing sequence you increase your number by 6.
T(n)=18+6(n-1)
for 603 to be in the sequence, it has to male sense with the function above
603=18+6(n-1)
603-18=585
585=6(n-1)
n-1=(585/6)
n=(585+6)/6
n=591/6
here is your answer.
Answer:
- a = 1.11
- B = 105.4°
- c = 2.95
Step-by-step explanation:
B = 180 -A -C = 105.4 . . . . sum of angles in a triangle is 180°
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The missing side lengths can be found from the Law of Sines:
a/sin(A) = c/sin(C)
a = c·sin(A)/sin(C) = 2.46·sin(21.2°)/sin(53.4°) ≈ 1.11
Likewise, ...
b = c·sin(B)/sin(C) = 2.46·sin(105.4°)/sin(53.4°) ≈ 2.95
Answer:
b
Step-by-step explanation:
Answer:
{0.16807, 0.36015, 0.3087, 0.1323, 0.02835, 0.00243}
Step-by-step explanation:
The expansion of (p+q)^n for n = 5 is ...
(p+q)^5 = p^5 +5·p^4·q +10·p^3·q^2 +10·p^2·q^3 +5·p·q^4 +q^5
When the probability p=0.3 and q = 1-p = 0.7 the terms of this series correspond to the probabilities of 5, 4, 3, 2, 1, and 0 favorable outcomes out of 5 trials.
For example, p^5 = 0.3^5 = 0.00243 is the probability of 5 favorable outcomes in 5 trials where the probability of each favorable outcome is 0.3.
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The attachment shows the calculation of these numbers using a graphing calculator. It lists them in reverse order of the expansion of (p+q)^5 shown above, so that they are the probabilities of 0–5 favorable outcomes in the order 0–5.